Hoffman Amplifiers Tube Amplifier Forum
Other Stuff => Cabinets-Speakers => Topic started by: 69SG on October 30, 2010, 09:40:11 am
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I built a 50 watt JCM800 type Head. 4>8>16 ohm selector.
Sometimes I use a 1>12" 16 ohm cabinet.
Sometimes I use a 2>12" 8 ohm cabinet.
Tell me if this is correct for using both cabs plugged in
8+16=24ohms divided by 2=12 ohms
Which selector setting is safer for the transformer
8 or 16 ohms
Thanx
WDB
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Speakers in series: Rt = R1 + R2 ... + Rn
Speakers in parallel: 1/Rt = 1/R1 + 1/R2 ... + 1/Rn, which resolves as Rt = (R1 * R2) / (R1 + R2)
For two speakers in //, 8R and 8R => 4R, 8R and 16R => 5.333R
Closest tap is 4R. As the actual impedance is anything but constant, you may obtain better results in the low and low/mids using 8R.
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> Tell me if this is correct -- 8+16= .... =12 ohms
Resistors in parallel, the total is always _less_ than any individual resistor.
Try some combinations you know.
8||8 is 8 your way, but we (should) know that two 8s in parallel is 4.
8 in parallel with 8,000, say a speaker with a NFB resistor or line-out tap: your way says 4,004 ohms. But we "know" that the amp will still feel that 8 ohm load, plus a teeny added load in the 8K, the real answer must be mighty close to 8.
Yeah, 8||16 works out to an odd number.
Also the 8 is probably taking 2/3rd of the amp power, the 16 only 1/3rd. Unless the 16-ohm unit does something much better than the 8, or you can cover some small area the 8 isn't hitting, you must wonder if it is worth hooking the 16 at all.
> safer for the transformer
Bah, no difference in "safer". Don't run NO load. If you have a choice, don't run 32 on the 4 tap.
5 ohms is lovely safe fit for 4 or 8. There may be some tonal difference depending on the speaker's actual impedance curve and the amp's characteristics.
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Let me go at this from a different direction.
If I have 3>16 ohm speakers paralleled.
what would be the prefered ohm setting on the output
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Lets see... 3-16R loads in parallel with each other.
1/((1/16)+(1/16)+(1/16)) = 1/(3(1/16))= 1/(3/16) = 16/3 = 5.333333R
(Side note, the final 16/3 may look like a shortcut: Speaker R/Quantity in parallel BUT that only works when the impedance is the same for each speaker.)
4 Ohm tap is closest and slightly higher impedance, 8 ohm tap is fine for a little lower impedance on the output tubes.
Hmmm.... FYL already answered this a bit back as far as impedance load Using only two values though.
PRR and FYL already came to the same conclusion I state as well as far as hook-up.
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yes the simplicity of it .
16 divided by 3
:embarrassed:
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16 divided by 3
Does it work with Divided by 13 amps?
:angel
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16 divided by 3
Does it work with Divided by 13 amps?
:angel
ROFL - You tell me :icon_clown: