Hoffman Amplifiers Tube Amplifier Forum
Amp Stuff => Tube Amp Building - Tweaks - Repairs => Topic started by: kagliostro on March 19, 2013, 02:41:19 pm
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The schematic is this
(http://licho.rowerpower.org/gitara/practic2_lite.gif)
and the transformers are those of this stereo amp
(http://s8.imagestime.com/out.php/i838089_KitHiFi02.jpg)
(http://s8.imagestime.com/out.php/i838088_KitHiFi01.jpg)
TA 230VAC 100mA - 13.5V 1A
TU 5k - 4 and 8 ohm
the rectified 230VAC gives near 320V, the schematic say B+ 280v and the pcl86 datasheet say max 250V plate (300V for the ecl86)
http://www.r-type.org/pdfs/pcl86.pdf (http://www.r-type.org/pdfs/pcl86.pdf)
http://www.nj7p.info/Common/Tube/SQL/Tube_query.php?Type=6GW8 (http://www.nj7p.info/Common/Tube/SQL/Tube_query.php?Type=6GW8)
However I noted there is a big difference in cathode resistor value, the guitar amp 170R the HiFi amp 330R
How you can get to square the circle ?
EDIT: I forgot to say that in the HiFi stereo amp there was also a 5H 100mA 41.2ohm choke who is disposable for the guitar amp
Thanks
K
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> 320V ... 280v
From 280V to 320V, for the same dissipation, you must use a 1.3 times higher resistor.
The tube levers the cathode resistor to make an equivalent resistor.
So it makes sense to find a larger resistor. 330/180= 1.8 times higher does seem strange.
> datasheet say max 250V plate
Is the tube inexpensive? Can you change it yourself? Then don't worry too much.
Build it, use the larger cathode resistor, measure dissipation, and adjust.
> How you can get to square the circle ?
http://rationalwiki.org/wiki/Squaring_the_circle (http://rationalwiki.org/wiki/Squaring_the_circle)
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Hi PRR
Many Thanks
Ok I can follow you about the change in value of the resistor because of the higher B+ voltage
where I'm still a bit confused is in relation with the OT primary impedance
I've seen schematics that say to use a 7k OT but the HiFi amp moreover the 322V B+ uses a 5k OT
in which manner this has effects on the circuit with the higher B+
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As there is disposable (from the HiFi amp) the choke (5H 100mA 41.2ohm) I think this will help on tamer a bit the B+, there is math that can help to predict which will be an expected voltage drop ?
Or better, can I use the same math used for a 41.2ohm resistor ?
Thanks Again
K
one other "squared circle" :grin:
http://en.wikipedia.org/wiki/Vitruvian_Man (http://en.wikipedia.org/wiki/Vitruvian_Man)
(http://upload.wikimedia.org/wikipedia/commons/thumb/2/22/Da_Vinci_Vitruve_Luc_Viatour.jpg/300px-Da_Vinci_Vitruve_Luc_Viatour.jpg)
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> can I use the same math used for a 41.2ohm resistor ?
Yes.
A good guess for load impedance is V/I of the tube. For 320V supply, 12W dissipation, about 300V across the tube, 12W/300V= 0.040A max current, and 300V/0.040A= 7,500 ohms. +/-30% is all the same.
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Many Thaks Sir (http://www.diyitalia.eu/forum/images/smilies/salutations-489.gif)
K