Hoffman Amplifiers Tube Amplifier Forum

Amp Stuff => Tube Amp Building - Tweaks - Repairs => Topic started by: Tone Junkie on April 22, 2013, 02:33:14 am

Title: Putting a resister across your pot to lower value
Post by: Tone Junkie on April 22, 2013, 02:33:14 am

Can any one tell me which is the right way. I forgot didnt keep notes on this one.
Thanks Bill
Seems I have developed (CRS) (cant remember shit) (LOL).

Title: Re: Putting a resister across your pot to lower value
Post by: stratele52 on April 22, 2013, 04:21:02 am

  " A " is the way.

Easy to see with an Ohmeter wich one you need .

Title: Re: Putting a resister across your pot to lower value
Post by: kagliostro on April 22, 2013, 04:41:38 am

The A solution is sometime used, but I can't say exatly what happens

Te B solution if you have a linear pot modify the response like in a Log pot

see here

http://www.geofex.com/article_folders/potsecrets/potscret.htm (http://www.geofex.com/article_folders/potsecrets/potscret.htm)

http://sound.westhost.com/pots.htm (http://sound.westhost.com/pots.htm)

K

Title: Re: Putting a resister across your pot to lower value
Post by: Tone Junkie on May 17, 2013, 02:05:34 am

Quote from: kagliostro on April 22, 2013, 04:41:38 am

The A solution is sometime used, but I can't say exatly what happens

Te B solution if you have a linear pot modify the response like in a Log pot

see here

http://www.geofex.com/article_folders/potsecrets/potscret.htm (http://www.geofex.com/article_folders/potsecrets/potscret.htm)

http://sound.westhost.com/pots.htm (http://sound.westhost.com/pots.htm)

K

Great article K.
Thanks Bill

Title: Re: Putting a resister across your pot to lower value
Post by: jojokeo on May 17, 2013, 10:58:31 am

A - just puts a parallel resistance across the pot's value.
B - just parallels the wiper's resistance through it's rotation.

Title: Re: Putting a resister across your pot to lower value
Post by: Tone Junkie on May 17, 2013, 03:47:01 pm

Thanks jojokeo I think I just want to parallel through the wipers rotation.  Which would be what Im really looking for, the simple answer seems to help me the best.
Bill