Hoffman Amplifiers Tube Amplifier Forum
Other Stuff => Solid State => Topic started by: kagliostro on April 25, 2013, 07:21:36 pm
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For a friend I'm drawing the schematic of an old italian guitar amp
it is a mixed amp with SS and Tubes
as I didn't understand SS at all, I'm not sure the schematic I've draw following the layout is correct
I'm not able to recognize if the Base - Emitter - Collector of the BC209 transistors are connected consistently
with the schematic, if I swap a grid or a cathode I can see by myself the mistake, but transistors are like arab language for me
Thanks for any help
K
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Q1 and Q2 are reasonable.
Q3 is surely wrong. So is the connection from Q2 to Intensita pot and tube grid.
Q3 *seems* to be a "switch" to short-out the tremolo signal. To do this, I would expect B and E the other way, and a source of current to the Base.
And it is still odd, because the Trem signal can go on the wire out to the foot switch, no transistor switch needed. So maybe Q3 is an emitter follower to buffer the trem signal?
Here's one way it might be done. I think you need to study it some more.
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Many thanks PRR
Q3 was the principal doubt I had (not thet Q1 & Q2 weren't a problem for me, but looks less odd to my eyes)
I'll further investigate about Q3
So may be there is a reason for which someone disconnected the wire from FottSwitch and Q3
I am indebted to you, really thanks
Franco
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The investigation give some result
the situation seems to be this (see schematic)
there is a wire that connect the wiper of the 10k trimmer to the emitter of Q3
there is also an unconnected wire, the wire that previously I've draw as connected between the emitter of Q3 and the FootSwitch
if someone can say something as to arrive at a solution he is welcome
Many Thanks
K
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BC109 data with pin-out:
http://www.tekkna.it/open2b/var/catalog/product/files/1428.pdf (http://www.tekkna.it/open2b/var/catalog/product/files/1428.pdf)
Perfectly modern NPN Silicon. (Yes, 40 years old!)
Pinout is referenced to a flat-spot on the body. I am not sure what I am seeing in the picture. However my *guess* is that C is grounded, E shorts-out the guitar signal through Intens knob, and B gets a portion of the trem oscillator, plus DC bias, through the pre-set trim pot.
And grounding the Base with jack or pedal stops the trem.
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Many thanks PRR
Now I know how is connected the transistor, how to connect the wire and, very important for my knowledge, how the circuit acts
Again I'm in debt to you
Franco