Hoffman Amplifiers Tube Amplifier Forum

Amp Stuff => Tube Amp Building - Tweaks - Repairs => Topic started by: tompagan123 on December 11, 2014, 04:56:53 pm

Title: Measuring output power?
Post by: tompagan123 on December 11, 2014, 04:56:53 pm
Greetings,

How do you all measure output power?  I've seen a YT video where Gerard Weber measures the AC volts across the speaker and applies ohms law to calcutate the power.  Easy peasy.  Anyone else do it like that?

Thanks again!

Tom
Title: Re: Measuring output power?
Post by: sluckey on December 11, 2014, 05:05:51 pm
I do.
Title: Re: Measuring output power?
Post by: shooter on December 11, 2014, 08:49:04 pm
Just finished calculating gains for each stage n overall Amp pwr.  Pre = 59, Pa=16.5  pwr =21.4 which shouldn't be since it's PSE el84's
Title: Re: Measuring output power?
Post by: HotBluePlates on December 11, 2014, 09:58:50 pm
Greetings,

How do you all measure output power?  ... measures the AC volts across the speaker and applies ohms law to calcutate the power.

General Radio made the 1840-A Output Power Meter (http://www.nousnexus.com/Manuals/GR_1840A_im.pdf). After you strip away all the bells & whistles, GR puts a resistance from hot to ground at the output of a device and measures voltage. The switching and metering is then calibrated to represent that voltage in terms of decibels and power (because the ultimate load resistance is a fixed constant; therefore, measured volts converts directly to measured power).

If you don't have a load resistor, you can just measure at the speakers terminals.
Title: Re: Measuring output power?
Post by: jjasilli on December 12, 2014, 08:59:35 am
Just finished calculating gains for each stage n overall Amp pwr.  Pre = 59, Pa=16.5  pwr =21.4 which shouldn't be since it's PSE el84's


I think power ratings are nominal by necessity.  Without measuring, output power can be calculated using the Ohm's Law power formula, and plugging in the plate voltage, and primary impedance of the OT (assuming a correct speaker load).


If you measure per a real speaker:  Does it's nominal impedance match the OT secondary?  If NO, then you get a different power reading.  If YES, still the speaker shows Impedance -- i.e., a different fixed resistance for every frequency.  The industry standard is 1000 Hz with a clean (undistorted) output wave; but different speakers will have a different resistance at any given frequency.  So the amp's output power reading may change with different signal frequencies, and with different speakers at the same frequency.


If you measure per a fixed resistor, similar complications persist.
Title: Re: Measuring output power?
Post by: tompagan123 on December 12, 2014, 09:10:56 am
Ah.. So then as far as signal quality at the measurement point, that would have to be subjective.  perhaps the highest voltage achievable for a clean sounding open E chord?    "clean for  a guitar amp could actually be a really high THD.   Maybe using Maj7 chord searching for the  point where it becomes dissonant would be useful?    I dunno, just wondering..
Title: Re: Measuring output power?
Post by: jjasilli on December 12, 2014, 11:32:31 am
Power is measured at one specific frequency, from a signal generator.  If there's a range of frequencies -- like from a music source; multi-note guitar chord; white or pink noise generator --  ea. frequency will be at different voltage, to the chagrin of your meter or 'scope, which are not designed to measure more than one voltage at a time (from the same signal).  There are multi-frequency analyzers.  They will show different wave heights for each frequency.  The wave height is the voltage at that frequency.  The wattage (power), is the Area Under the Curve of the Waveform.  That will vary with each frequency.


A similar issue exists with regard to the horsepower of a gasoline engine. It varies with RPM and other factors.  So, the stated horsepower is nominal (and might even be complete hogwash).
Title: Re: Measuring output power?
Post by: PRR on December 12, 2014, 02:56:10 pm
> calculating gains for each stage n overall Amp pwr.  Pre = 59, Pa=16.5  pwr =21.4

I do not follow that math.

And gain is not power. What if I had a guitar that put out 10 Volts? Looks like 50,000 Volts out, WOW! Yet as we know, two EL84 can only make 12V or 13V across 8 Ohms.

Speaker is dubious. An "8 Ohm" speaker is above 16 Ohms in much of the guitar power spectrum, and can touch 50 Ohms on the lowest notes. You can easily get an "impossible" reading.

Power tests are quite simple and standardized.

Since there is always distortion, figure how much distortion you will call "clean". In low-fi work this is often 5% THD.

Load with a *resistor*. Because of the many different impedances of real speakers, loudspeaker tests are always run on a resistor.

Feed a sine-wave input. Start mid-band, perhaps 400Hz. For extra fun, later repeat the test across the audio spectrum.

You will generally want any Master Volume FULL up... you are measuring final stage output, not what you get from preamp strain.

Increase level until you hit the THD number.

Without a THD meter, use a 'scope. Increase until the wave is clearly bent. Decrease until not bent. Find a point in the middle where wave is slightly bent. Call that the power.

While you are set up, turn the level up to very-bent and leave it that way for a long time. Then turn down to half of just-bent and leave it that way. This covers the maximum-abuse conditions. If an amp is over-worked, these tests may cause a failure (better on the bench than at the gig). (Max-abuse for class-A is idle, but you've probably run that test already.)

There is also the early-Traynor technique. Again, a mid-band sine into a resistor, but you use an Averaging meter (old passive needle-meter) and find the maximum you can get. This will typically be rounded squares out, 50+% THD, and 1.5X-2X the "clean" power output. In some sense, this is "cheating", but in guitar-land it is appropriate for highly overdriven tones. It also tells directly the thermal power that the speaker may have to handle.

You can instead use a Peak-to-Peak voltmeter (some not-all VTVMs). For clean-clipping amps, the P-P reading will rise to a point and then plateau, even as you crank more signal through. Back off a bit from that plateau and call it Power. This will be good for push-pull 6L6/6V6 with NFB, dubious for the EL types, and often way-wrong for single-ended amplifiers (which clip asymmetrically).

It is always useful to have a low-level monitor speaker across the load resistor. The meter will not tell you if the amp is making weird sounds as it strains. Often the progression of harmonic overtones is more musically interesting (or distressing) than the actual power. Put 100 ohms in series with a speaker and bridge that across the load resistor.
Title: Re: Measuring output power?
Post by: Jim Coash on December 20, 2014, 03:23:27 pm
Greetings:  Of all the questions I had to deal with during my 40 years in the A/V business, those dealing with power were the most frustrating.  So many times I lost a sale to another store because the salesperson there managed to convince the customer that his package offered more "watts" for the money.  We all are familiar with Ohm's law, but its relationship to power is so difficult to explain.  I always had to give a detailed explanation about speaker impedance, efficiency, headroom, bandwidth, IM, THD, RMS and Peak power.  Almost always to someone who could not really understand the science.  The most common statement I made with regards to power was that watts were to speakers as horsepower is to tires.  Speakers do not have watts, tires do not have horsepower.  The amount of power a speaker can handle has much more to do with clipping than actual measured wattage.  Distortion, not power, damages speakers.  When you hear distortion coming though a speaker it is almost always the speaker playing the amplifiers distortion, seldom the speaker itself distorting.  Of course, tube amps clip smoothly with pleasing overtones and harmonics which is why we love them and why they do not cause damage as often as solid state amps.  Suffice it to say that over driving a transistor amp is not pleasant and I find it clearly audible long before damage occurs.  In more than 40 years of using sound re-enforcement systems of very high power and quality I have NEVER damaged a driver.  I have repaired dozens of speakers with damaged speaker elements.  Invariably, getting the customer who damaged his/her speakers into more efficient speakers (like E/Vs) or a larger amplifier (like Carver Pros) solved the problems for good.  I choose to do both.  My gig (performing) system uses active crossovers, the largest amps available and the best speakers I have ever found.  Jim
Title: Re: Measuring output power?
Post by: jjasilli on December 20, 2014, 04:35:29 pm
". . . watts were to speakers as horsepower is to tires.  Speakers do not have watts, tires do not have horsepower."


Generally, your points are well taken, but the quoted statement is incorrect.  Tires are not rated in terms of horsepower, but speakers are rated in watts.  Watts are not something that a device "has".  The wattage rating states how much power the device can consume, produce or transfer, without risking damage (likely to be caused by overheating in a device rated in watts.)


Ohm's Law clearly states that electrical power is: Watts = Vsquared / Resistance.  But this holds for DC current only.  It  does not directly apply to AC such as musical signal.  AC is the realm of Impedance, not Reistance.  The nominal load of a speaker, such as 4 or 8 ohms, is often used.  But the wattage so stated wil only be true for a linear waveform at a frequency which actually "sees" that specific load.

Title: Re: Measuring output power?
Post by: 2deaf on December 20, 2014, 07:07:59 pm
Power is measured at one specific frequency, from a signal generator.  --  ea. frequency will be at different voltage

You can measure power at any frequency the power tube will handle as long as you know the load impedance.  The amp doesn't care about the original source of the signal.  The maximum voltage will only vary with frequency if the load varies with frequency.  So if you have a constant load (like a resistive dummy load), the voltage is going to stop at the same maximum point whether the signal is a 1KHz sine wave or white noise.  That point is what amp manufacturer's are going to use when they rate their amps since it is the maximum before a wave clips.     
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 07:52:56 pm
". . . watts were to speakers as horsepower is to tires.  Speakers do not have watts, tires do not have horsepower."

Generally, your points are well taken, but the quoted statement is incorrect.  Tires are not rated in terms of horsepower, but speakers are rated in watts.

I think Jim meant that speakers don't have watts (the amplifier does), any more than tires have horsepower (the engine does).

Ohm's Law clearly states that electrical power is: Watts = Vsquared / Resistance.  But this holds for DC current only.  It  does not directly apply to AC such as musical signal.

That is a false assertion. The Equation for Power is a fundamental electrical relationship which always holds true.

Ohm's Law is Current = Voltage / Resistance (or any algebraic permutation of that statement).
The Equation for Power is Power = Voltage * Current (no mention of alternating or direct current).

You can replace the term "Current" in the equation for power with the Ohm's Law statement above it, and yield Power = V2/R.

"Impedance" at the end of the day is "opposition to current" same as "Resistance." The only difference is impedance includes the frequency-variable quantity of opposition, Reactance. If you need a universal equation, replace "Resistance" in any of the above formulae with "Impedance;" they'll all still work exactly the same, and if you calculate the reactance at any frequency of interest and use vector algebra to combine that with resistance to get the correct resulting impedance and phase angle, then all the math still works the same.

... The nominal load of a speaker, such as 4 or 8 ohms, is often used.  But the wattage so stated wil only be true ... at ... that specific load.

The edited quote above is an accurate statement (though the complete original statement was not).

It's like this:

If you change the load of an amplifier while changing nothing about the amplifier, the power transferred to the load will change. This is described by the Maximum Power Transfer Theorem (http://en.wikipedia.org/wiki/Maximum_power_transfer_theorem). The issue gets complicated when you move from "Maximum power is delivered when an 8Ω load is attached to the 8Ω tap" to what's happening inside the amplifier with loading of tubes. So stick with what's in quotes in the previous sentence.

Also, the amplifier itself has high and low frequency roll-offs, so above some high frequency power output will fall, and below some low frequency power output will fall. So you need to pick a point mid-band to measure output power.

Now, acknowledging a speaker does not have a single, constant impedance, and that changing the loading away from some ideal value reduces power output, you land at the recommendation to measure power by using a resistor as the amplifier's load. There is still a.c. across that load resistor, but now you don't need to worry about the resistor's effective value changing. All the math above still applies (though you may have to be smarter than the math to recognize complicating factors, such as a big mid-range dip due to the tone circuit at the 400Hz you planned to use as a test tone).
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 07:53:20 pm
But the wattage so stated wil only be true for a linear waveform at a frequency which actually "sees" that specific load.

What is a "linear waveform"?

What I think you meant was a non-distorted sine wave. Really, you can use any stable, repeating waveform, though we typically use sine waves because 1) it makes the math easier, and 2) it's easier to pick a frequency where the amplifier's overall frequency response doesn't skew your results. You could also restate the 2nd point as a clean sine is a single frequency instead of a composite of multiple frequencies, and so a swept sine wave makes frequency response measurements easier to interpret.

Now maybe you were referring to Wikipedia's article on Audio Power (http://en.wikipedia.org/wiki/Audio_power). The wild-looking integral in the 1st equation under "Power Calculations" in the end says "Power = Volts * Current" but uses the integral to convert any waveform into an effective-average over time. Which is the same thing we do when we convert alternating sine-wave voltages to RMS (http://en.wikipedia.org/wiki/Root_mean_square); at the end of the day, we're still converting the a.c. to a "... value ... equal to the direct current (DC) that delivers the same average power to a resistor ..." so that the simple to use equation at the top of this post can be used.

So I'll use a sine-wave test tone and a load resistor to measure output power. Or you can use any waveform at all, if you're willing to do integral calculus on that waveform to get an average over time. If you have to be able to use any signal shape, you can again use a load resistor and an IR temperature sensor to measure heat thrown off by the resistor, because that will still be proportional to power output; the resistor does the integral calculus (average power in the form of heating of the load) for you.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 07:56:55 pm
You can measure power at any frequency the power tube will handle as long as you know the load impedance. ... the voltage is going to stop at the same maximum point whether the signal is a 1KHz sine wave or white noise.

I agree with you, but using a sine (single frequency) will be easier for interpretation (as I mention above).

The problem becomes an issue of test-tone bandwidth vs. amplifier bandwidth. And if you throw enough power through a transformer, it will constrict bandwidth more, and now you have yet another factor to interpret.

There are good reasons, based in fundamentals of electronics and a knowledge of how amps work, which caused the "usual test methods" to become the usual test methods.
Title: Re: Measuring output power?
Post by: jjasilli on December 20, 2014, 08:13:36 pm
Yes, I meant an output waveform that matches the shape of the input waveform without deviation (distortion).  I.e. the "lines" of the waveforms are shall we say "congruent", differing only in amplitude but not in shape.  So, sometimes described as linear.  The "lines" will be curvy except for square or sawtooth waves or the like.  The difference in amplitude is a given -- it belies the need for amplification of the input signal to begin with. 


But even the mere change in amplitude is an issue.  As amplitude increases significantly even a sine wave begins to approach the characteristics of a rectangular wave.  Put another way, a sine wave in ouput, stretched very tall in amplitude, will no longer be linear with respect to the initial, nicely rounded sinewave at the input.
Title: Re: Measuring output power?
Post by: jjasilli on December 20, 2014, 08:20:28 pm
Power is measured at one specific frequency, from a signal generator.  --  ea. frequency will be at different voltage

You can measure power at any frequency the power tube will handle as long as you know the load impedance.  The amp doesn't care about the original source of the signal.  The maximum voltage will only vary with frequency if the load varies with frequency.  So if you have a constant load (like a resistive dummy load), the voltage is going to stop at the same maximum point whether the signal is a 1KHz sine wave or white noise.  That point is what amp manufacturer's are going to use when they rate their amps since it is the maximum before a wave clips.


Yes, but as hotblue intimates, if you strum a chord, all the notes (frequencies) may not be at the same voltage.
And the use of a dummy load to measure output power is fine, but is another form of compromise.  It does not measure the performance of the amp as actually used into a dynamic speaker load. 


Moreover, it takes more power (wattage) to raise bass notes to the same voltage as treble notes.  This is because power is equal to the area under the curve of the waveform.  And there's always more area under the bass note curve (given the same voltage), because bass notes have a longer baseline due to their longer frequency.  So it takes more watts to output a 12vac bass note than a 12vac treble note. 
Title: Re: Measuring output power?
Post by: PRR on December 20, 2014, 08:30:09 pm
> Tires are not rated in terms of horsepower, but speakers are rated in watts.  Watts are not something that a device "has".

Horsepower and Watts are the same thing.

1 Horsepower is 746 Watts.

You often see European engines rated in W (or kW) instead of HP.

We rarely rate audio amps in HP because it would look bad. A Fender Twin is 0.06HP. Less than most model airplane engines.

Tires "could" be rated in HP, but it isn't simple. One big difference is that 98% of the power you put in a tire goes to the road. 98% of the power you put into a speaker stays IN the speaker.

If we used tires by jamming the bumper against a wall and spinning the tires, then there would be some use in a Horsepower rating. But there isn't a lot of use for that. Yes, exhibition "drifting", but those guys need more than just smoke, and an HP rating is not much direct use.
Title: Re: Measuring output power?
Post by: PRR on December 20, 2014, 08:33:31 pm
> power is equal to the area under the curve of the waveform.

The treble wave does the same power *more* times per second. More power?

Assuming resistance, the power is the same either way.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 09:05:42 pm
But even the mere change in amplitude is an issue. 

Well, everything is, or can be, an issue. The real question is will you settle for it all being unknowable, or is there value in knowing at least something about what the amp does?

For instance, in any car, there are hundreds or thousands of tradeoffs and interactions happening when you push the gas pedal. But most will not look at it as unknowable magic, but see a simple fact of "I push the gas pedal further, the car goes faster" (up to some limit).

And the use of a dummy load to measure output power is fine, but is another form of compromise.  It does not measure the performance of the amp as actually used into a dynamic speaker load. 

We can stipulate this fact; a speaker load will behave differently than a resistor load. The answer to understanding an amplifier's capability is to have a simple starting point, then layer on the additional factors which will alter the answer.

The simple starting point is a resistor load and a sine test frequency, at some maximum level of distortion measured at the resistor. To get the ball rolling, assume distortion is zero when power output is measured, and the load resistor matches the OT tap's specified load impedance.

One can increase the test signal strength until distortion appears, and then back it down just until the point of maximum voltage output and zero distortion. Now you measure the RMS voltage output and apply the math to get the maximum clean output power. You could also look at the size of your test signal and say, "For the point where this signal is injected, it represents the largest signal which can pass cleanly to the final load." That might be important if something in the entire amp circuit could distort before the output tubes. It might also be useful to apply the test signal directly at the output tube grids, if you have a signal source which is clean and can generate those large voltage swings.

Now if you look at a plot of speaker impedance (http://www.eminence.com/pdf/Cannabis_Rex.pdf) (the faint line on the graph linked), you'll notice that the rated 8Ω is the lowest impedance in the usable frequency range; when you move away from ~300Hz where the speaker is truly 8Ω, the impedance rises. This may have an effect on the amplifier's output power. But to know if it will, you have to know something about the amplifier. Knowing nothing else, we should assume power transfer will b less than perfect because the load isn't matched, so clean output power is lower than our first measurement with a resistor. If nothing else, you will know clean output power cannot be any higher than the value measured with the resistor.

If you used a sine wave for the resistor measurement, you also know something else: Peak power output is double the measured RMS output power (take this on faith for a sine wave, or I can bore you with the math derivation). If the sine wave was so distorted it became a square wave, then the peak power output would be equal to the RMS power output, so you just found something else useful from using a sine and a resistor load: worst-case speaker heating is double your maximum measured clean RMS power output, and you can rate the speaker accordingly if you want to prevent it from blowing.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 09:06:06 pm
I said the changing impedance of the speaker "may" effect the amp's output power for 2 reasons. Your amp may have negative feedback around the output stage, which will minimize or eliminate the effect of varying load impedance on output power (until you drive the output stage so hard the feedback is overwhelmed). There may also be a less-than-ideal designed load impedance due to available output transformers. The GR 1840-A I mentioned earlier in this thread has a transformer to reflect 42 different impedances from 0.6Ω up to 32kΩ. It does this so you can switch loads quickly to determine the output impedance of the device under test, where the greatest output power is delivered.

So the raising of load due to changing speaker impedance could result in more or less output power, and more or less distortion. If the amp was designed well with the perfect OT and no negative feedback, the output power should drop and/or distortion increase when the load impedance increases.

Now back to the notion of injecting the test signal directly at the output tubes. Say you did that, and arrived at a certain maximum clean power output. Then you move the signal-injection point to the input of the amp, and reduce the signal by the amount of amplification you expect between the input jack and the output tube grids. But something weird happens: the measured maximum clean output power is lower than the first test. Now you know the amp circuit distorts somewhere before the output tubes, either by design or by error.

You could also start at the output tube grids with your testing, and sweep the signal frequency from 80Hz up to some maximum (maybe 10-15kHz, if you like). If you carefully recorded each resulting maximum clean output power and plotted these on a graph, you'd have the frequency response for the output stage. You could repeat at all earlier stages, and see how each stage contributes frequency-shaping to the final amp output (like the tone circuit impacts I mentioned earlier). Or you could just start at the input jack and skip the intermediate stuff, or measure voltages to graph the frequency response at any stage other than a power output stage.

Now, knowing the biggest output tube grid-signal input that will allow clean output power at the resistor load, you might evaluate how/whether the pickup's peak output tends to momentarily distort, and where in the amp, when you're playing your guitar at your fave settings. It won't change the limiting values you found earlier, and it won't change the maximum clean output power the amp is capable of producing. It might inform your understanding of how you get "fuzzy clean" when the initial transients of your playing distort momentarily while the bulk of the signal is cleanly amplified. Maybe that will influence how you design an amp. Or not.

There's probably a hundred other things we could get into about what will limit or impact clean power output, but I don't believe that's important beyond informing how you should set up the test. At least not when the question was "How to Measure Output Power?"
Title: Re: Measuring output power?
Post by: jjasilli on December 20, 2014, 10:07:50 pm
"Well, everything is, or can be, an issue. The real question is will you settle for it all being unknowable, or is there value in knowing at least something about what the amp does?"


Personally, I'm happy with the Ohm's Law DC power calculation, without measuring signal.  But this thread is originally about measuring, not bare calculation.  In the end I think we're stuck with apples vs. oranges comparisons, because often, test criteria are not fully divulged.
Title: Re: Measuring output power?
Post by: sluckey on December 20, 2014, 10:28:00 pm
Maybe the good doctor will come along soon and provide some obscure university library reference to enlighten us.   :icon_biggrin:
Title: Re: Measuring output power?
Post by: HotBluePlates on December 20, 2014, 10:35:15 pm
Personally, I'm happy with the Ohm's Law DC power calculation, without measuring signal.

Well, if I can't convince you Ohm's Law and the equation for power apply to a.c. and not just d.c., then I don't think we'll get very far.
Title: Re: Measuring output power?
Post by: jjasilli on December 21, 2014, 07:49:30 am
To clarify, I'm happy calculating an amp's output using the plate voltage squared / the OT's prmary impedance, without measuring signal. 
Title: Re: Measuring output power?
Post by: HotBluePlates on December 21, 2014, 09:27:31 am
Oh, gotcha. Now your replies make sense in context. Sorry...
Title: Re: Measuring output power?
Post by: shooter on December 21, 2014, 10:17:16 am
I think tires would be better rated by applied torque, I could get my engine to last 5 years, but my tires only lasted about 4mths!

Good discussion btw!
Title: Re: Measuring output power?
Post by: jjasilli on December 21, 2014, 12:00:51 pm
> power is equal to the area under the curve of the waveform.

The treble wave does the same power *more* times per second. More power?

Assuming resistance, the power is the same either way.


This is true but does not tell us the Power that the amp puts out to produce bass vs. treble frequencies at the same voltage.


Empirical example: a 2-way hi-fi speaker has a woofer & a tweeter.  The crossover sends only about 1/3 of the power to the tweeter, and still the tweeter may be to loud with respect to the woofer and need more attenuation.  Next, the speaker may be bi-amped with a separate power amp driving each speaker-driver.  The tweeter's power amp need be no more than 1/3 the power of the woofer's power amp.


I think this is roughly analogous to leverage in a mechanical system.  It takes 100 ft-pounds of energy to raise 100 pounds one foot.  But if we use a pulley system we can pull one foot at a time, do it 10 times, and expend only 10 ft-pounds of energy per pull.  Likewise an amp may put out only 10W of power to drive a treble frequency to a certain voltage level (the peak of the curve), but need to put out, say, 30W to drive a bass frequency at that voltage.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 21, 2014, 12:24:14 pm
> power is equal to the area under the curve of the waveform.

The treble wave does the same power *more* times per second. More power?

Assuming resistance, the power is the same either way.

This is true but does not tell us the Power that the amp puts out to produce bass vs. treble frequencies at the same voltage.

You're lurching towards the unknowable again with complicating factors.  :icon_biggrin:

Equal-voltage across a resistance load is the same as equal-power. So if the amp puts out power to the load resulting in equal voltage for some high- and some low-frequency, then there is equal power at those 2 frequencies.

Your example about reduced power to the tweeter really has more to do with Fletcher-Munson Curves (http://www.webervst.com/fm.htm), and the fact that your ear doesn't respond to all frequencies the same. Moreover, your ear's relative response to different frequencies changes for different loudness levels (with more variation at softer ear-loudness).

Really, this has little bearing on an amplifier's clean power output, except with regard to measuring at high- and low-enough frequencies to determine where the amp's overall frequency response rolls off (for instance, due to OT characteristics and/or roll offs resulting from the use of caps at different places in the amp).

...  Likewise an amp may put out only 10W of power to drive a treble frequency to a certain voltage level (the peak of the curve), but need to put out, say, 30W to drive a bass frequency at that voltage.

You haven't stated an impedance for the woofer & tweeter. If they are the same, then equal voltage means equal power (proved by the equation for power). If they're different, the driving voltage is different for the same-power; if you need different-power because your ear hears upper-mids much better than lows (proved by Fletcher-Munson), then you can't make an easy comparison.

Now before you say "A-Ha! The speaker's impedance is all over the place, so now we really don't know," keep in mind the speaker's impedance is rising at upper mids and highs, which we assumed before would cause a well-designed amp to have reduced output power.

Anyway, we are still going far, far afield of the point: What's the maximum clean output power the amp can deliver into a specific load? Which is what we'd be measuring. If you need to determine without doubt the performance of an amp/speaker combination, you go get an anechoic chamber, a measurement microphone, and set it up to measure the resulting performance. But unless you're manufacturing hi-fi or speakers, you don't need anything approaching that level of complexity.
Title: Re: Measuring output power?
Post by: Jim Coash on December 22, 2014, 06:18:50 am
Greetings:  I love this discussion!  Your comments are exactly the kind of responses I have expected and have been dealing with all my life.  I am not an engineer with a degree, just an old man with a lifetime of experience.  So many times others have disputed my statements about power.  All I am really saying is that I have sold hundreds (thousands?) of pairs of speakers and amplifiers and found that  the people who ultimately damaged their speakers did so because of a lack of power, not by having too much.  So many times I have sold a very large amp to a person who destroyed his speakers with a 60/WRMS/channel receiver and then never had a failure again.  This includes setting them up with a power amp rated to deliver far more power than their speakers were "rated" at.  Music is a difficult thing to describe, quantify or replicate on a test bench.  A speaker load is far more complex than a resistor.  Specifications on amps and speakers are all over the board and seldom reliable.  My main premise is simple;  virtually any well designed speaker or speaker system can handle any amount of clean, un-distorted power but none can handle clipping distortion for long.  Solid state amps using the original transistors available in the late 60s and early 70s (prior to MOSFET) were notorious for damaging speakers.  Few people were equipped to actually tell when the clipping was occurring and they eventually overheated the voice coils and damaged speakers no matter what the power rating might have been.  On the other hand, I have been routinely using very large power amps to drive all manner of speakers for more than 40 years without EVER damaging a driver.  This is thoroughly tested in sound re-enforcement situations because I have been a working DJ since the late 60s.  Frequently someone comes up to me during a gig and wants to know "where my subwoofers are".  I point to the E/V 12" unit in front of my table and they shake their head in disbelief.  The secret is a Carver PM-600 run mono driven by the E/V System 200 controller (an active crossover at 100hz) and a pair of E/V SX-200 speakers driven by another Carver Pro.  Incredible SPLs.  No distortion.  Jim
Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 08:53:36 am
Jim, you're right for sound systems.  But electric guitarists in certain music genres love overdrive and distortion and are willing to risk breaking their amps or speakers to get it!


Back to practicality re amp output power.  To reiterate, to me the simplest way to get an "indication" of the amp's performance is to calculate it using the Ohm's Law Power Formula: Watts = Voltage2  / Resistance.  Voltage is the plate voltage; resistance is the nominal primary impedance of the OT primary. 


Next per tompagan123's 1st post above: is the Gerard Weber method measuring the AC volts of a clean signal, just before it "goes dirty" across the speaker and applies ohms law to calculate the power.  One obvious problem is that the signal may be going dirty in the preamp or PI, while the power tubes still have more clean headroom of watts to put-out.  This could be further investigated with a 'scope or a listening amp.  The industry standard is 1KHz; lower frequencies may be more useful for guitar, but there are no universal standards.  A lack of standards raises the issue of apples & oranges comparisons.  Also the results will vary from speaker to speaker.

Next, also mentioned above is to use a dummy load resistor, usually = to the nominal impedance of the speaker. But, here's a typical Eminence guitar speaker @ 8 ohms nominal:  http://www.eminence.com/speakers/speaker-detail/?model=GA_SC64#   Note that the pdf spec sheet puts most of the guitar frequency spectrum at about 90 Ohms!  So the standard use of an 8 Ohm dummy load resistor will give an "indication" of the amps performance which could be used to compare one amp to another; but may not specify the output performance of any particular amp > a speaker.  Note also that Eminence is kind enough to give reasonably detailed info about how it's measurements are done, without which its numbers & charts would be largely meaningless.

There is no way around these things.  Any particular method results in a "knowable" number.  But there is no universally accepted method or standard, so the comparison of these numbers is frustrating.







Title: Re: Measuring output power?
Post by: 2deaf on December 22, 2014, 11:22:40 am
How do you all measure output power?

If you take a typical transformer output tube guitar amp rated at 100Wrms, set the selector for 4 ohms, put a big-ass 4 ohm resistor in place of the speaker and turn the amp up, then the thing puts out 100Wrms from about 50Hz to 15KHz before clipping (usually right before clipping).  If you do the same with a 50Wrms amp, it puts out 50Wrms.  The maximum non-clipped RMS output wattage of your amp is a really handy thing to know and all of that other stuff doesn't matter. 
Title: Re: Measuring output power?
Post by: Jim Coash on December 22, 2014, 12:05:34 pm
Excellent responses all.  Over 40 years my interest in discovering ways to accurately portray the relationships between, amps, speakers, distortion and listening preferences left me wondering how I could possibly develop some kind of "unified theory".  Just like Hawking, Einstein before him and Newton before him, I finally concluded that the best I could do was to quantify the variables, nail down the parameters and present my thoughts with a grain of salt.  A large grain of salt.  I also am a player and I just love the sound of an over driven tube amp.  Of course it proved much easier to do that with my Fender PR (Princeton Reverb) than with the TR (Twin Reverb), depending on the venue.  My wife could not stand my driving the big amp that far, especially with the E/V-12G speakers in place of the original Oxfords.  Fortunately, we all have access to many different stomp boxes that provide the distortion we crave at the pre-amp level.  I also added a switch on the TR that allows one speaker at 8 ohms or two at 4 ohms to be selected.  I also replaced the ground switch with a NFL selector so I could choose either normal, none or 1/2 of the usual amount.  My goal, probably due to my audio influences has always been to make my guitar amps as clean, quiet and dynamic as I possibly can.  That is my baseline.  Even in a large room I can generate massive volume levels with clarity.  I also added a pre-out jack to both Fender amps.  That way I can patch either into my PA/gig rig when needed while still getting the crunch I like for most of the music I play.  I sold home A/V products for many years including speakers from at least two dozen highly respected companies.  I could find no correlation by comparing "spec" sheets.   When I read the E/V and then the JBL white papers on power handling I found the answer I was in search of.  No matter what a company says about their speakers ability to handle power, they can be damaged by over diving a small amp into clipping and still remain perfectly safe when used with an amp rated for several times more power than they are rated for.  I run that experiment every time I perform.  Even my Electro Voice system is not rated to handle the kind of power I have available with the amps I use.  The reason I have NEVER damaged a driver is simply because I remember the old adage from a Clint Eastwood movie;  "A man's gotta know his limitations"!  No distortion.  Ever.  Jim
Title: Re: Measuring output power?
Post by: 2deaf on December 22, 2014, 01:05:17 pm
calculate it using the Ohm's Law Power Formula

There is an Ohm's law and there are power formulae, but no "Ohm's Law Power Formula."  Wikipedia has no match when searched.  Didn't HBP already set you straight on this?
Quote
Watts = Voltage2  / Resistance.  Voltage is the plate voltage; resistance is the nominal primary impedance of the OT primary. 

Then how come I can flick my 60W/100W switch and get 60W instead of 100W when the nominal impedance is still the same and the plate voltage actually increases a little?
Quote
One obvious problem is that the signal may be going dirty in the preamp or PI, while the power tubes still have more clean headroom of watts to put-out.

Then don't do that.
Quote
The industry standard is 1KHz; lower frequencies may be more useful for guitar, but there are no universal standards.

Which industry standard is that?  The maximum wattage is the same for all guitar frequencies.



Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 01:36:00 pm
By the Ohm's Law Power formula I mean the one in which you're solving for Watts and know Voltage and Resistance.  The Pie Chart is attached.



Then how come I can flick my 60W/100W switch and get 60W instead of 100W when the nominal impedance is still the same and the plate voltage actually increases a little? 
Because the formula is voltage squared.  So a small change in voltage makes a large difference in watts.  (Depending on the amp, other circuitry may also come into play.)


Then don't do that.
 :laugh:   Not an easy choice.  You need to give the power tubes enough signal to start getting dirty, then dial back a tad.  By then, depending on the amp, the preamp or PI may already be distorting.  So if yo begin hearing "dirt", it may not be from the power tubes.  The power tubes may be providing a clean boost to a signal that's already gotten dirty.  So, the power tubes may have more clean signal voltage to put across your speaker load that isn't obvious just by listening for dirt.


Which industry standard is that? 
The audio industry.


The maximum wattage is the same for all guitar frequencies.
Yes, but an amp will it the max wattage for bass frequencies long before it hits the max wattage for treble frequencies.  That's one reason for bi-amping.









Title: Re: Measuring output power?
Post by: Jim Coash on December 22, 2014, 02:30:49 pm
I recommend bi-amping or even tri-amping for every application using more than one driver element.  The current trend in powered speakers bears out my thinking.  Using multiple amps and active crossovers eliminates much of the distortion and power losses passive crossovers introduce into any system.  Naturally, most combo amps use either one speaker or more than one of identical types so no crossover is needed.  Consider that in a two way system, as much as 90% of the power is actually devoted to the low frequencies.  That is why woofers are always much larger than tweeters.  Low frequencies appear to be a much smaller percentage of the spectrum but they require much more energy to reproduce.  The best place to use bi-amping is always the lowest crossover point; the subwoofer.  That frequency is usually 100hz or lower.  Removing all of the frequencies above 100hz takes a tremendous load off of the amp that can be devoted to driving the frequencies above 100hz.  If practical, another active crossover point between mid and highs and two more amps will yield a major improvement.  The new compact sound re-enforcement speaker systems with on board amps are made that way with a separate amp for midwoofer and tweeter making use of a low level active crossover at signal level.  My main home A/V system uses a Carver Signature Sub with high pass filter and a pair of Carver Pro power amps, one driving highs, the other mids.  The main speakers are KEF Reference Ones.  It is easy to think about a speakers voice coil as just a coil of wire of a certain gauge with a fixed resistance.  When you place that coil in a strong magnetic field, wrapped around a hi-temp Teflon former with Pro-Tef technology and drive it with music it becomes much more difficult to quantify.  The motion of the voice coil makes it an air pump so cooling occurs normally.  That holds true only if the voice coil is constantly moving with a true sine wave input.  It breaks down when those waves become square as amp clipping is reached.  A speaker can reproduce clipping distortion if it occurs at pre-amp level but not for long if it is the result of amp clipping.  Jim
Title: Re: Measuring output power?
Post by: sluckey on December 22, 2014, 02:39:16 pm
Quote
By the Ohm's Law Power formula I mean the one in which you're solving for Watts and know Voltage and Resistance.  The Pie Chart is attached.

Technical foul... Ohm's law has nothing to do with power. Never did. It deals with voltage, current, and resistance ONLY.  5 yard penality! repeat 1st down.  :icon_biggrin:

"OHM’S LAW—The current in an electric circuit is directly proportional to the electromotive force in the
circuit. The most common form of the law is E = IR, where E is the electromotive force or voltage
across the circuit, I is the current flowing in the circuit, and R is the resistance of the circuit."

     NEETS Appendix 1, page A1-5.
Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 03:16:45 pm
I stand corrected and plead guilty with an explanation.  I picked up the Pie Chart long ago, with a reference from this Forum to these nice people:  http://www.the12volt.com/ohm/ohmslaw.asp#pie (http://www.the12volt.com/ohm/ohmslaw.asp#pie)  who call the entire set of equations on the chart the Ohm's Law Pie Chart, and that's what I've been doing ever since.  So it seems the Power Formulae belong to Watt's Law. 


Sorry for the confusion in the terminology.  However, a power formula by any other name is still a power formula, and the points made remain the same.



Title: Re: Measuring output power?
Post by: 2deaf on December 22, 2014, 03:17:31 pm
By the Ohm's Law Power formula I mean the one in which you're solving for Watts and know Voltage and Resistance.

I know what you mean, but it is not titled "Ohm's Law Power Formula".

Quote
Then how come I can flick my 60W/100W switch and get 60W instead of 100W when the nominal impedance is still the same and the plate voltage actually increases a little? 
Because the formula is voltage squared.  So a small change in voltage makes a large difference in watts.

Yeah, but the voltage increased by the square making the wattage on the 60W setting even higher.  Let's just say the voltage stays the same.  60W is still inconsistent with your power hypothesis.

Quote
Then don't do that.
    Not an easy choice.  You need to give the power tubes enough signal to start getting dirty

I don't give a FFF about dirt and apparently guitar amp manufacturer's don't care much more about it than me.  It's just the maximum output signal that determines what these things are being rated at, regardless of the nature of the signal.  Hi-Fi cares about THD and other distortions that can cause their ratings to be less than the clipping point, but guitar amps don't.

Quote
Which industry standard is that? 
The audio industry.

Any particular standard within the overly-broad category of "audio industry"?

Quote
The maximum wattage is the same for all guitar frequencies.
Yes, but an amp will it the max wattage for bass frequencies long before it hits the max wattage for treble frequencies. 

So?  Even if it were true (which it isn't), there is still the maximum wattage and that is all that we are concerned with.   
Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 03:37:31 pm

2deaf:I think at this point we're going in circles.


Watt's (not Ohms!!!) has a law; it's not my hypothesis.


I can't speak to your particular amp without a schematic.


I don't give a FFF about dirt and apparently guitar amp
This is the Gerald Weber method, posted above by tompagan123 (http://el34world.com/Forum/index.php?action=profile;u=3302).  This method is fine with me. To me, it's another form of useful compromise to measure output power.  You don't have to like this method, but you should take that up with Mr. Weber.


there is still the maximum wattage and that is all that we are concerned with
Not necessarily true, especially when playing full chords.  If the bass notes breakup 1st then the chord will sound dirty even if the hi notes are still clean.


At this point we may wish to start a thread on how to measure bias.  ANY TAKERS?  :l2:


 







Title: Re: Measuring output power?
Post by: 2deaf on December 22, 2014, 04:00:38 pm

2deaf:I think at this point we're going in circles.
Fine.  I notice you kept on going, so I guess we can ignore the geometry.

Quote
Watt's (not Ohms!!!) has a law; it's not my hypothesis.

You're hypothesis was that you can determine the wattage of an amp using the plate voltage and the nominal impedance of the primary winding.  I presented a case that was inconsistent with this hypothesis.

Quote
there is still the maximum wattage and that is all that we are concerned with
Not necessarily true, especially when playing full chords.  If the bass notes breakup 1st then the chord will sound dirty even if the hi notes are still clean.

I don't think this is circular.  This is responding to something other than what was stated.

Quote
At this point we may wish to start a thread on how to measure bias.

I always love this one and the confusion about which negative number is larger.
Title: Re: Measuring output power?
Post by: Jim Coash on December 22, 2014, 04:09:57 pm
Well, I am interested in adjusting bias.  My PR now has a solid state rectifier and Iv'e replaced all the caps and resistors in the amp with better new ones.  I also have incorporated the bias circuit found in EL34's notes on Fender amps.  I increased the size of the bias cap, drilled a hole in the chassis and mounted a pot, grounded the bias resistor that was fixed to the pot and now I am wondering if I dare plug the thing in.  When I did many of the same things to my TR I took it to a good tech I know and he started it up on his Variac.  He found a couple small problems but after he addressed those it came up just fine, new tubes and all.  A little tweak with the bias and all done.  Wow is that amp great!  I can select either one or two EV-12G speakers, either factory NFB, none or half of factory with a switch and add whatever distortion I want with a stomp box.  That Twin Reverb can go from sounding like a small wattage amp to a screaming clean monster in just a moment.  With the pre-out I can put whatever I want into the PA mix too.  I just wish it wasn't so heavy.  That's why I'm doing the Princeton Reverb.  Jim
Title: Re: Measuring output power?
Post by: drgonzonm on December 22, 2014, 05:10:10 pm
Just finished calculating gains for each stage n overall Amp pwr.  Pre = 59, Pa=16.5  pwr =21.4 which shouldn't be since it's PSE el84's


I think power ratings are nominal by necessity.  Without measuring, output power can be calculated using the Ohm's Law power formula, and plugging in the plate voltage, and primary impedance of the OT (assuming a correct speaker load).


If you measure per a real speaker:  Does it's nominal impedance match the OT secondary?  If NO, then you get a different power reading.  If YES, still the speaker shows Impedance -- i.e., a different fixed resistance for every frequency.  The industry standard is 1000 Hz with a clean (undistorted) output wave; but different speakers will have a different resistance at any given frequency.  So the amp's output power reading may change with different signal frequencies, and with different speakers at the same frequency.


If you measure per a fixed resistor, similar complications persist.

Could you quote your source for industry standard.  It is my understanding that speakers are rated at its nominal ohms at 400 Hz, while the amplifier power readings are conducted at 1KHz, as you have stated.  (It is my understanding that the 400 Hz, is geometric average for the human voice, while the 1KHz is the geometric average for human hearing.  )  (The reference for 400 Hz is an old Western Electric publication). 

I agree with you that power readings should be conducted at 1KHz.  A resistive load is acceptable. Like most people, I don't really want to be around a blaring 1KHz sound.   

Will I see a "standard response"?

Remember people, Ohm's law is empirical.  For the most part, it works.
Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 06:09:53 pm
I was trying to gracefully end this discussion -- at least my role in it, due to a lion's share of the attention.  But it seems there is still interest & fair questions are being asked.


It seems to me that the stated output of an amp is akin to the stated horsepower of, say, a gasoline engine -- a topic I'm sure is rife with discussion on such other forums.


Anyway:  here's some corroboration of the 1KHz industry standard:  http://www.diyaudio.com/forums/tubes-valves/15489-measuring-amp-output-power.html (http://www.diyaudio.com/forums/tubes-valves/15489-measuring-amp-output-power.html)  For further corroboration I call to the witness stand Hotblue.  This topic has come up before on this Forum.  My recollection is that he has recommended it more than once, along with 400Hz (440 maybe??) as more appropriate to a guitar amp. 


But audio industry standards may be too rigorous or barely applicable to the rough & tumble niche of guitar amps.  Hence the rough & tumble method of the venerable guitar amp guru Gerald Weber, about which 2deaf states he couldn't give "FFF" about, because 2deaf is a fixed-resistor dummyload measuring guy, end of story -- thereby making my point. 











Title: Re: Measuring output power?
Post by: Jim Coash on December 22, 2014, 06:23:32 pm
Ohm's law is empirical and it works like a simple, reliable formula for most circuit work.  Mathematics is difficult for me.  I always reached a point in college where the math became more than I could deal with.  Dyslexia, I think.  All those years in the audio business forced me to deal with printed specification sheets that varied wildly, did not seem to apply in real world comparisons and were often more harm than help when trying to help someone select the right equipment for their needs.  Common questions sometimes could not be answered with simple answers.  "How many watts are those speakers"? was one of the most common.  If I quoted the printed wattage from a factory spec sheet, say 100 watts, the inevitable conundrum was did that mean they had to buy an amp or receiver with less wattage?  Those of us who love tubes know that trying to compare two instrument amps, one with tubes and the other with transistors just doesn't really work.  I own several fine tube amps ranging from a Fender Princeton Reverb rated at 12 watts (a pair of 6V6 tubes) to the Fender Twin Reverb rated at about 100 watts (four 6L6 tubes).   My Ampeg with a pair of 6L6s is rated at 60 watts.  All of those amps produce impressive volume levels.  For playing music at weddings and parties I use a stereo 3-way speaker system with an active E/V S-200 System Controller and a single Carver solid state amp, run mono, that is rated at over 1000 watts for the 12" sub and either a single Carver at 600 watts/channel for the mains or two of the Carver amps run mono for twice that much.  As I have previously stated, I have never damaged a single driver element in more than 40 years of DJ work.  That includes playing in very large venues, including out doors, often for more than 4 hours continuously at very high volume levels.  Technically, even the E/V speakers are not rated to be safe with that much power.  I contend that any good speaker is safer with a larger amp rather than a smaller one.  How can you accurately measure power other than by using a fixed frequency or frequencies and a load resistor?  Reactive loads are just that; reactive.  Impedance may vary wildly from well below rated "nominal" to way above and content material in music is impossible to quantify.  Trying to specify power numbers and ratings for amps or speakers is like trying to heard cats.  Next to impossible and not really relevant in the real world.  Agreed?  Jim
Title: Re: Measuring output power?
Post by: sluckey on December 22, 2014, 06:24:14 pm
Cross examine?

"L.A. Law" TV Intro (http://www.youtube.com/watch?v=e7R6ycC_s1g#ws)
Title: Re: Measuring output power?
Post by: HotBluePlates on December 22, 2014, 06:37:03 pm
... to me the simplest way to get an "indication" of the amp's performance is to calculate it using the Ohm's Law Power Formula: Watts = Voltage2  / Resistance.  Voltage is the plate voltage; resistance is the nominal primary impedance of the OT primary. ...

Yes, you can get an indication that way but you have to be aware of pitfalls.

The main one is you have to know something about the operation of the amplifier. Absolute theoretical maximum output power you could come up with using a knowledge of supply voltage and OT primary impedance is (B+2/√2)/(Primary Z/4). This equation assumes the output stage moves into Class B territory (one side of the push-pull stage is cut off) and the output tubes can pull their plates all the way down to 0v.

But no tube can pull its plate to 0v (though some can get "close enough"), and you may not be running the output stage in Class AB or Class B. If the output tubes are running class A (not class A for small signal and crossing into class B for large signals), then the bottom of the equation becomes Primary Z/2. You can fool yourself thinking you'll run a tube with high B+ in Class A and estimate a very high power output, when in reality the tube plate will melt. You can also fool yourself about the output capability of a class AB stage and overestimate the capability of a stage that's biased just a bit beyond class A (the high peak currents working far into class AB, which yield high output powers, also require large bias voltages to keep the tube within dissipation limits).

I bring that up because the reduction of clean output power as you take a simple class AB amp and bias the output tubes hotter, to get closer to Class A operation, is both a mathematical certainty as well as readily observable with any amp using no math and only a try-n-see approach.

The 1/√2 factor converts from peak voltage swing to RMS volts (assuming sine wave a.c.). Otherwise you'll calculate peak watts and (with a sine wave output to the load) estimate double the RMS power output.

I think you'll see without care, it's easy to mess up.

... Next, also mentioned above is to use a dummy load resistor, usually = to the nominal impedance of the speaker. But, here's a typical Eminence guitar speaker @ 8 ohms nominal:  [/font]http://www.eminence.com/speakers/speaker-detail/?model=GA_SC64#   Note that the pdf spec sheet puts most of the guitar frequency spectrum at about 90 Ohms!  ...

Frequency of Musical Pitches (http://www.phy.mtu.edu/~suits/notefreqs.html)

A440 is the 1st string, 5th fret on your guitar if you're tuned to A440. For my 21-fret guitar, that puts the top note, D, at just shy of 1.2kHz. The usual rule of thumb is to say there are few, if any, fundamental pitches above ~1kHz, leaving everything above as overtones of the notes you play (or harmonics due to distortion).

Comparing to Eminence's graph, that puts almost all guitar notes at/below 15Ω, except for that huge spike at 88Hz (pretty much right at the F on your low-E string). Catch is, this is the resonant frequency of the speaker, the frequency at which it moves most freely. Power delivered from the amp to the speaker may be well-reduced due to the impedance rise, but the speaker will play that note very much louder than all others. The 2 situations offset each other, to the point it's not worth worrying about.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 22, 2014, 06:53:08 pm
I was trying to gracefully end this discussion -- at least my role in it, due to a lion's share of the attention. ...

I hope you don't feel like we're beating up on you. That's not my intent, anyway.  :laugh:

... here's some corroboration of the 1KHz industry standard:  http://www.diyaudio.com/forums/tubes-valves/15489-measuring-amp-output-power.html (http://www.diyaudio.com/forums/tubes-valves/15489-measuring-amp-output-power.html)  For further corroboration I call to the witness stand Hotblue.  This topic has come up before on this Forum.  My recollection is that he has recommended it more than once, along with 400Hz (440 maybe??) as more appropriate to a guitar amp.

I didn't read the linked thread, so I'll apologize in advance if I look silly.

The chart I linked shows 1kHz is above most of the fundamental tones of the guitar amp, so it may be less relevant. It sits pretty-near perfectly in the middle of a log-plotted frequency spectrum of human hearing. I'm thinking of a 100Hz-1kHz-10kHz range. Top of human hearing is around double the top end of that (at 20kHz), while the bottom limit of hearing is a bit beyond half of the bottom end (at 50Hz). Yes, humans can hear lower (my limit, tested when I was young was around 16-18Hz), but you quickly get into rumble which is very difficult to distinguish as distinct musical tones. And humans have been shown to be able to sense the presence of frequencies up to around 48kHz, even you're not aware of "hearing" them (scientific tests reported by AES on this were part of the argument for higher sampling rates in digital recording than the CD standard of 44.1kHz).

So to  pure scientist, 1kHz is "mid-band" of hearing.

EDIT: Oops! Forgot to mention Fletcher-Munson again; your ear is most sensitive near 1kHz, so there's another reason.

The guitar range of ~80Hz-1kHz (not counting overtones or distortion) implies a lower pitch would be better for testing in the "mid-band" of a guitar amp. I think I even argued for 400Hz in the past after noticing that being a recommended test pitch somewhere in RDH4.

I now think you might want something more like 200Hz or 500Hz might be better, though you still need to know something about your amp's circuitry. Why? After looking at Duncan's Tone Stack Calculator, your Fender blackface tone stack has a nice deep notch at about 500Hz, so your power output measurement might be low. The exact frequency of such a mid-notch varies a lot depending on your particular tone circuit.

All of the above may be an argument for testing at a number of different frequencies, or for injecting the test tone at the phase inverter or output stage itself.
Title: Re: Measuring output power?
Post by: Willabe on December 22, 2014, 07:24:13 pm
At this point we may wish to start a thread on how to measure bias.  ANY TAKERS?  :l2:

Ooh, Ooh, pick me! With an O scope!    :laugh:

I always love this one and the confusion about which negative number is larger.


Ooh, Ooh, I know this one too,

-45 is larger than -58 because it's less negative.


                  Brad      :l2:   
Title: Re: Measuring output power?
Post by: sluckey on December 22, 2014, 07:29:00 pm
One outta two ain't bad.  :wink:
Title: Re: Measuring output power?
Post by: Willabe on December 22, 2014, 07:35:38 pm
There BOTH correct!!!!!

Which do you say is wrong?


                    Brad     :icon_biggrin:


(Sluckey, Shhhhh, I'm trying to start up some fun!)
Title: Re: Measuring output power?
Post by: 2deaf on December 22, 2014, 07:38:33 pm
Hence the rough & tumble method of the venerable guitar amp guru Gerald Weber, about which 2deaf states he couldn't give "FFF" about, because 2deaf is a fixed-resistor dummyload measuring guy, end of story -- thereby making my point.

Heh, heh, heh.  I don't even know what your point is let alone how I made it for you.  I don't know who Jerry is or what his method is, but when you can consistently derive the manufacturer's specifications with a particular experiment, it really lends a lot of credibility to the method.

Yes, you can get an indication that way but you have to be aware of pitfalls.


I have no doubt that if I gave you all the values of all the parameters of a PA you could calculate the actual output wattage and it probably wouldn't take you very long, either.  However, just knowing the theoretical maximum isn't going to do much more than give you an "indication" and I am talking about actually determining the wattage.  Weighing a push-pull OT is another way to get an "indication". 
Title: Re: Measuring output power?
Post by: jjasilli on December 22, 2014, 07:58:36 pm
At this point we may wish to start a thread on how to measure bias.  ANY TAKERS?  :l2:

Ooh, Ooh, pick me! With an O scope!    :laugh:

I always love this one and the confusion about which negative number is larger.


Ooh, Ooh, I know this one too,

-45 is larger than -58 because it's less negative.


                  Brad      :l2:   


You're reading my mind, brother.   :occasion14:
Title: Re: Measuring output power?
Post by: Willabe on December 22, 2014, 08:30:13 pm
 :laugh:     :occasion14:
Title: Re: Measuring output power?
Post by: PRR on December 22, 2014, 09:16:12 pm
> speakers ability to handle power, they can be damaged by over diving a small amp into clipping and still remain perfectly safe when used with an amp rated for several times more power than they are rated for.

There is a total dichotomy between "music reproduction" systems and "music production" systems.

Yes, often over-powering is safer if you NEVER clip. And in a fixed installation the weight of the hyper amp is moot.

Stage musicians in many genres USUALLY push FAR past clipping.

Partly because the dynamics of a bare string are boring. Lack the emphasis of hard-pushed voice or reed. The rise of overtones in clipping gives the guitar some of this dynamic expression.

Also because stage amps often must be _carried_ twice a night. Watts are heavy. Nice-clipping Watts (tubes) are extra heavy. I'm not gonna carry 1,300 Watts and then not-clip it, if 50 Watts of heavy clipping does the same job and probably lighter.

Now, how do speakers survive?

Guitar speakers ARE different from Hi-Fi speakers.

A Hi-Fi speaker may say "100 Watts", but a steady 20 Watts will cook it.... the maker relies on the >~10dB peak/average ratio of not-badly-clipped "music". Also a woofer with extended bass can be over-excurded with 10 Watts at 30Hz. While many listeners will push to clipping, gross clipping of full-band material throws so much intermodulation that it becomes unpleasant.

OTOH, a guitarist does not cover the whole spectrum. The guitarist can only play 6 notes at once, and selects them so their IM products suit musical tastes. So he can tastefully(?) play far into clipping.

How do our speakers stand it? There are *limits* to our abuse. A "25 Watts" (sine at clipping) amplifier will deliver almost 50 Watts of hard-clipped Square Wave. Because speaker efficiency is 6%-1%, essentially all of this heat goes to the coil. Modern speaker glues will hold-together at 50 Watts of raw heat in the coil. Excursion is limited by very *stiff* suspensions-- typical Hi-Fi Fs is 40hz, typical g-speaker Fs is 80Hz-- *four* times the stiffness. (Maybe 3X because cones are lighter.) Also coils are short. Typically the coil can be driven out of the magnet without damage. (Once the coil gets out of the magnet it stops trying to move more.)

This is a careful compromise and there IS a way to blow-up many guitar speakers. Play Bass through them HARD. The octave-down stimulation is twice as likely to stretch things beyond limits. This is not an invariable rule, some guitar speakers handle big bass, but many have been torn this way.

This type of use/abuse is reflected in the speaker ratings. A "100W" Hi-Fi speaker may melt at 20 Watts steady power. A "25W" guitar speaker will absorb *50 Watts* of thermal abuse all night. I have in fact used an older "25W" EV speaker as a 36 Watt DC dummy-load.

As for death of Hi-Fi systems-- many users (dancers are the worst) will turn-up to some high level of intermodulation. Often the "best" speaker for them is a small 2-way with a very high crossover. The gross bass excursion IMs the midrange clarity to get the "haze" they associate with "loud", at somewhat modest thermal power. Yes, excess electric power is needed or the tweeters will burn. (And these users often do not miss them.)
Title: Re: Measuring output power?
Post by: PRR on December 22, 2014, 09:36:42 pm
> a total dichotomy between

Just hit an analogy, though it may not be common-experience.

How heavy should an engine be?

In a "car", engine power is good, engine weight is very bad. Engines should be as light as possible. (Moreso in airplanes. Less so in long-range trucks where weight buys extended life.)

In a Dirt Tractor, a light powerful engine will just spin its wheels/treads. Working on dirt you need WEIGHT to get Traction. Of course you could throw dead weight on the tractor, but if there is ANY excuse to build the engine heavier, you build it as HEAVY as you like.

Real dichotomy between the two applications.
Title: Re: Measuring output power?
Post by: Jim Coash on December 23, 2014, 12:31:51 am
My first really good audio amp was a McIntosh 2100.  It was heavy for its rated 105wrms/channel.  I carried it around for years.  When I worked at "The Sound Room", first in the service department, we had a clinic put on by McIntosh each year.  They would measure any amp brought in by our customers using a scope, load resistor, signal generator and just run a 1kz tone through the unit, observe the waveform and measure its peak to peak and then generate a few inches of graph paper that showed the THD from 20 to 20k.  It was consistent and repeatable.  Some companies. Harmon/Kardon comes to mind, disputed the usefulness of this test.  The claim was that  their amps were wideband designs that were essentially flat to a much higher frequency.  The McIntosh people said that was irrelevant given the limits of human hearing.  I eventually owned two H/K Citation 19 amps that could be run mono at nearly 4 times the power of the 2100.  Going from 100 to 400wrms did give me more volume; 6db more, which was useful.  What made much more difference was changing from speakers that sounded great but were approximately 92db/w/meter to E/V speakers that were over 102db/w/meter.  That 10db difference was  a bigger usable increase in output.  When I eventually tried Phase Linear 700 amps I realized not only another increase in power but a big reduction in the weight I had to carry to gigs.  After using many different amps and speakers I finally arrived at the Carver/Electro Voice system I still use today.  Another big change was changing from carrying three TEAC reel machines for sources to DAT and finally CD.
A similar evolution occurred with my guitar amps as it did all over the world.  Musicians went from needing huge stage amps like Marshall double stacks and Ampeg SVT amps to using smaller amps that sounded great and then patching them into huge PA rigs which finally became available as technology caught up with the demand.  Imagine what The Beatles would have sounded like using today's sound systems!  If you have heard one of the clone versions like "1964: The Tribute", you know.  Jim 
Title: Re: Measuring output power?
Post by: shooter on December 23, 2014, 08:06:14 pm
I'm no math wiz so laugh, I'm liken -58 as the larger  number especially if you are trying to get to -100, your closer than the guy in the 40's........anyway       I use 2 meters, 1 scope, n 1 10ohm 250watt 1% resistor, and 1 ToneGen software, not to try n conform to the worlds standard, just so when I get the next amp done, my  previous numbers will already be apples.
Title: Re: Measuring output power?
Post by: SoundmasterG on December 24, 2014, 12:00:54 am
"Well, everything is, or can be, an issue. The real question is will you settle for it all being unknowable, or is there value in knowing at least something about what the amp does?"


Personally, I'm happy with the Ohm's Law DC power calculation, without measuring signal.  But this thread is originally about measuring, not bare calculation.  In the end I think we're stuck with apples vs. oranges comparisons, because often, test criteria are not fully divulged.


But this is only a theoretical number and not representative of what is coming out of your amp. I built an amp that has four 7868's, 460V, and a 2500 ohm plate to plate impedance. It should be almost 85 watts....but it is around 50 watts instead and is functioning fine and correctly. Just one example of my point.


Greg
Title: Re: Measuring output power?
Post by: jjasilli on December 24, 2014, 08:39:03 am
Greetings,

How do you all measure output power?  I've seen a YT video where Gerard Weber measures the AC volts across the speaker and applies ohms law to calcutate the power.  Easy peasy.  Anyone else do it like that?

Thanks again!

Tom


Quoted above is how this thread started, and why the Weber method is relevant.  Everyone is entitled to make their own point.  In essence my point has been that there are 3 ways to determine output power: 1.  calculate it using the power formula; 2.  measure it into a resistive load; and/or 3. measure it into a reactive load (Weber being a simplified approach).  Ea method is "valid", but has its pro's & cons.  Also, they are likely to yield different outcomes from one another.  And, the latter two methods may yield inconsistent results with themselves, depending on exactly how the test is done.


This I submit is a statement of objective reality and should be non-controversial.  Any controversy seems to arise from the person's subjective preference, possibly to the degree of undue bias (pun intended per my prior post, but try measuring that  :icon_biggrin: ), as to which method they prefer. 






Title: Re: Measuring output power?
Post by: 2deaf on December 24, 2014, 01:37:13 pm
there are 3 ways to determine output power: 1.  calculate it using the power formula; 2.  measure it into a resistive load; and/or 3. measure it into a reactive load

What about weighing the transformer?
Title: Re: Measuring output power?
Post by: Jim Coash on December 25, 2014, 05:44:51 am
Actually, when people ask me how they can know that an old chassis is worth buying, I tell them, the heavier it is, the more likely it is worth something.  That way if they can barely pick it up, they know I want it.  If it ways little or nothing, leave it alone.  Jim
Title: Re: Measuring output power?
Post by: 2deaf on December 25, 2014, 11:26:46 am
Actually, when people ask me how they can know that an old chassis is worth buying, I tell them, the heavier it is, the more likely it is worth something.

I was just joking, but if you know how many primary wires there are and the weight, you really can make an educated guess about the wattage.  If you also happen to know the nominal primary impedance, you can make an even better guess.  The size of the main fuse and how much the lights dim in your house when you first turn it on can give you a clue.  How many output tubes and the size of the bottles can give a clue.  The number incorporated into the name of the model frequently gives a clue.  The number near the output jack(s) usually accompanied by the letter "W" or the word "watts" is usually a really good clue.  If you want to know what your amp can really put out, you're gonna have to measure it.

Merry Xmas 
Title: Re: Measuring output power?
Post by: darryl on December 25, 2014, 03:54:22 pm
If the amplifier is factory built, always keep in mind that the watts quoted by the Sales Department can be distinctly different to the watts measured by the R&D Department.
Title: Re: Measuring output power?
Post by: Jim Coash on December 26, 2014, 10:04:48 am
During my years in the A/V business I represented many different brands, most of them, the more highly respected ones.  Over the years most of those brands went through changes of ownership and/or philosophy.  Today, when someone tells me they just bought something based on brand reputation I cringe.  There are many examples, but recently I was contacted by a client who could not figure out how to hook up his new TV.  The name on the unit was one he knew from days long ago.  A name that once meant American made, quality and local service availability.  His new TV bore no resemblance to those ideals.  There was only a single RF stud on the rear.  No HDMI, composite or other input, no audio out, not even a headphone jack to connect it to his A/V system.  I was able to use the RCA outputs on his cable box to get audio to his system but there was no way to connect his DVD player to the set.  It had RGB, HDMI, composite outs but no RF in/out.

My point about measuring power is that in my career, spanning more than 50 years, every brand of amp, receiver or integrated used their own method of measuring power making it impossible to compare.  The most conservative methods specified were using a system based on WRMS/chan/20to20k/.1%THD (or less)/w3db headroom (or more) and those numbers were from companies like McIntosh, Carver, NAD, Harmon-Kardon and the like, at least when those brands were respectable.  Onkyo, Yamaha, Electro Voice, QSC, Crown and a few others were also reasonable.  Most others, not so much.  Some were downright ridiculous.  Giving a number for one channel, at 1000hz, 1%THD with no headroom specified yielded specifications that were of little practical use.  These were all solid state ampsby the end of the 70s, generally used for home audio but some also usable in sound re-enforcement apps.  Classic tube amps are really not comparable in a meaningful way because valves and transformer coupled outputs are so different.  MOSFET and some other later solid state devices did permit some comparisons but direct coupled bi-polar output stages simply are a different animal.

I own some very good solid state amps that I do use for instrument work.  My Ampeg BA150 is a respectable unit.  Using my tube pre-amp Hafler Hellraiser to drive a large solid state amp like my E/V 1.5 or any of my Carver Pro amps sounds good through my many E/V cabinets either factory or custom made.  I have an E/V loaded Mesa-Boogie box with an EV-15B in the bottom, an EV-12G and an EV-10 in the top that is really great and so flexible now that I re-built it with a jack plate that allows the top and bottom to be separated or used together or bi-amped.  But the underlying truth is this; the more "real" power I have, the better my speakers sound and the safer they are.  Jim
Title: Re: Measuring output power?
Post by: 2deaf on December 26, 2014, 01:27:39 pm
I suggest we take a clue from component suppliers, take Hammond for example, a lot of their  OT's reference 1K Hz as a reference.   (While the engineers at Jensen will say Hammond does not provide enough information, it is starting point.)  Hammond then provides an operating range for the OT.

Hammond typically rates their wattage within a range of frequencies and that wattage will only deviate a specified amount plus or minus as compared to the wattage at 1 KHz.  I don't know if that's what you said or not.

Title: Re: Measuring output power?
Post by: jjasilli on December 29, 2014, 02:06:46 pm
Yes, different test conditions will produce different results.  E.g., the Stromberg Carlson 1100 APH manual (100W mono bloc PA power amp) states that the amp produces 100W @ 5% Harmonic Distortion; 80W @ 2% Harmonic Distortion, over much of the range of human hearing.  But it doesn't state specific test conditions, such as the test frequenc(ies) used, or into what load.  I assume Stromberg Carlson means that within the stated frequency range, no frequency will have more than the stated distortion at 80W or at 100W, in the actual & proper use of the amp and its speaker load.  But they don't actually say that.

Assuming that both 80W & 100W are both honest measurements of the same amp under different but valid testing conditions, that's a very large spread if you're a builder or manufacturer trying to sell amps to the general public. 

This doesn't mean that power output is "unknowable" as HotBlue has "accused" me of advocating; but that stated wattage is not an absolute in itself, and needs to be knowledgeably interpreted in terms of how the test was done.  Without that background info the stated wattage may be meaningless or unreliable.




Title: Re: Measuring output power?
Post by: 2deaf on December 29, 2014, 03:16:55 pm
From reviewing some old books on audio transformers.  (Norman Crowhurst, seems to know what he is talking about),  I believe the 1k Hz reference and the range of frequencies, refer to two different standards. 

It is my understanding, that 1k Hz, as a standard is the close to the geometric mean of the range of human hearing, so a single point parameter can be used.  Then from some undocumented research, (I was looking info on a Western Electric handset), Western Electric gives 400 Hz, as the geometric average of the human voice.  (you would be surprised how many things are engineered using single parameter formulas). 

As a followup, 

Fender Music in its 1995 Blues Jr schematic. uses a 1kHz sine wave as an input reference.  Other conditions are stated.  Output is 13.1 watts.  The 1995 blues Jr., IMO, provides superior documentation.

Stomberg-Carlson in its au-33_ps-33 uses a 400Hz signal to define its output power.
Uuummm...Okey-dokey.
Title: Re: Measuring output power?
Post by: 2deaf on December 29, 2014, 04:13:13 pm
But it doesn't state specific test conditions, such as the test frequenc(ies) used, or into what load.
They spell out the range of frequencies so there is that specific test condition.  You can tell they are using a constant load for their ratings because the response is damn flat and I don't think anybody would entertain the possibility that they used mis-matched loads.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 29, 2014, 04:21:52 pm
This doesn't mean that power output is "unknowable" as HotBlue has "accused" me of advocating; but that stated wattage is not an absolute in itself, and needs to be knowledgeably interpreted in terms of how the test was done.

"Uknowable" was just a running joke. Speaking plainly, I meant that you were taking a very simple, objective issue (measure volts across a resistance load to compute actual output power) and complicating it with extra factors until it became complex and subjective. The hope was we could agree on the simple, then build outward with an awareness of added real-world complications.

Yes, different test conditions will produce different results.  E.g., the Stromberg Carlson 1100 APH manual (100W mono bloc PA power amp) states that the amp produces 100W @ 5% Harmonic Distortion; 80W @ 2% Harmonic Distortion ...  But it doesn't state specific test conditions ...[/font]

Sure they do. "100W @ 5% Harmonic Distortion; 80W @ 2% Harmonic Distortion" There is an implied, "with rated load attach to the output transformer secondary." In a testing environment, that's very likely to be a resistance load (we can debate whether this is a fact, but show me a test lab measuring power amplifiers which doesn't do it).

We've said this another way several times in this thread. If you had a distortion meter attached to monitor the output, and THD was measured as 0.000000001%, you will measure one level of power output. If you increase the driving signal to the amp until 2% THD is measured at the output, you will also measure higher Volts RMS across the load resistor, and have "more power output." Increase drive signal again until 5% THD is measured across the load resistor, and measured Volts RMS and output power are again increased.

This increasing-power effect of a distorted signal runs into a limit where RMS power is double the RMS power of a clean sine output; this is the same as the RMS power of a square-wave, where RMS and peak power are the same. A square wave (http://en.wikipedia.org/wiki/Square_wave) is an infinite series of odd-harmonic sine waves added to a fundamental sine wave. While testing amps with a square wave has many uses, a sine wave consisting of only a single frequency is typically used for power tests because the results could be gimmicked when multiple tones are present (meaning, presence of distortion & artificially-high power measurements are harder to detect).

So Stromberg was very straightforward in their power rating: "this amp is 80w if you need 2% THD, but 100w if 5% THD is acceptable." 5% THD was once set forth as an amount that was minimally-audible and a benchmark for "Hi-Fi" performance.

In the flyer 2deaf posted, Stromberg implies the AU-33 will output 25w, at 5% THD over a bandwidth of 50Hz - 10kHz.

There was a game some transformer and hi-fi makers played with bandwidth numbers at one time. A transformer's power through-put tends to be pyramid-shaped: if you reduce the power applied below the transformer's rated power output, parasitic losses are reduced and the transformer appears to reach both lower and higher frequencies. So a transformer maker could spec a part as "50w output power" and "20Hz to 50kHz" but not tell you the frequency range quoted was measured for 1w of through-put. Then when you apply a full 50w, you get something more like 100Hz-10kHz.

Hammond is very proud of their full-power bandwidth specs, so when they say "30Hz to 30kHz" they mean at the full rated power of the part. You could really pass more power through one of their transformers if you're willing to forgo full power, as low.

But the point I tried to make repeatedly is that these are all side-issues if the question is "how do I measure the amp in front of me." The answer still remains, "attach a resistor as a load, inject a test signal, measure volts across the resistor, mathematically convert to power output." If you have the ability to measure or delineate distortion, then add to the procedure, "... at ___ measured % THD." If bandwidth/frequency response is desired information, then add to the procedure, "... tested at W, X, Y, Z frequency, or over X-Y frequency range."

In reality, the low end of response is going to be set largely by the value of the coupling caps used, followed after by the capabilities of the output transformer. The upper end of frequency response is going to be set by any shunt capacitances used (e.g., plate load bypass caps, "enhance caps," etc), followed after by the parasitic characteristics of the output transformer. All of the above might be modified by the use of negative feedback around the output transformer & output stage, to widen frequency response to a limit.
Title: Re: Measuring output power?
Post by: jjasilli on December 29, 2014, 04:27:50 pm
SC's range of frequencies is 50 - 15,000Hz @ 5% distortion; 40 - 20,000Hz @ 2%.  Did they test thousands of frequencies?  Or just 1KHz, and assume the rest?  Into a resistive load, or a speaker load?
Title: Re: Measuring output power?
Post by: jjasilli on December 29, 2014, 04:30:54 pm
But the point I tried to make repeatedly is that these are all side-issues if the question is "how do I measure the amp in front of me." The answer still remains, "attach a resistor as a load, inject a test signal, measure volts across the resistor, mathematically convert to power output." If you have the ability to measure or delineate distortion, then add to the procedure, "... at ___ measured % THD." If bandwidth/frequency response is desired information, then add to the procedure, "... tested at W, X, Y, Z frequency, or over X-Y frequency range."

Fine with me, but you too will need to take that up with Gerald Weber, whom advocates an actual speaker (reactive) load!   :icon_biggrin:
Title: Re: Measuring output power?
Post by: darryl on December 29, 2014, 05:10:47 pm
Fine with me, but you too will need to take that up with Gerald Weber, whom advocates an actual speaker (reactive) load!   :icon_biggrin:

That method would allow an amp builder to shop around for a speaker which had an impedance curve which optimised the output of the amplifier under test.

I agree with HotBluePlates. For comparing like with like, measure the output voltage across a load resistor at the onset of clipping, when driven with a continuous 400Hz or 1kHz signal.

If you have the necessary test equipment, quote additional information, such as the distortion. If you consider your amplifier has particular attributes which enhance its perceived output, quote those as additions to the raw output calculated with a resistive load.
Title: Re: Measuring output power?
Post by: jjasilli on December 29, 2014, 06:06:05 pm
Yes, I'm sure Weber advocates his method 'cause it's "Easy peasy" as tompagan says in the initial post to this thread.  All you need for equipment  is your amp hooked up to its usual speaker, your ears, and a volt meter.  Back to pro's & cons again.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 29, 2014, 06:30:10 pm
SC's range of frequencies is 50 - 15,000Hz @ 5% distortion; 40 - 20,000Hz @ 2%.  Did they test thousands of frequencies?  Or just 1KHz, and assume the rest?  Into a resistive load, or a speaker load?

Stromberg almost certainly used a resistor load (again... see the General Radio Power Output Meter I linked at the start of this thread; GR was one of, if not the, biggest test equipment manufacturers back in the day).

Stromberg said also "50Hz to 10kHz, within +1db, -2dB." That implies they swept the test frequency over that range while measuring voltage across the load, monitoring for voltage deviation, which then gives the number of dB above/below the nominal power output. Hewlett Packard made a Sweep Oscillator to span 20Hz-20kHz in a single dial turn (http://hparchive.com/Manuals/HP-207A-Manual.pdf), facilitating such measurements; they also made a bunch of other oscillators to cover this range and more if you were willing to flip a range knob.

Once you realize the test equipment available and the intended use, these arguments over "1kHz or 400Hz?" and "1 frequency or many?" start looking very silly.

But the point I tried to make repeatedly is that these are all side-issues if the question is "how do I measure the amp in front of me." The answer still remains, "attach a resistor as a load, inject a test signal, measure volts across the resistor, mathematically convert to power output." If you have the ability to measure or delineate distortion, then add to the procedure, "... at ___ measured % THD." If bandwidth/frequency response is desired information, then add to the procedure, "... tested at W, X, Y, Z frequency, or over X-Y frequency range."

Fine with me, but you too will need to take that up with Gerald Weber, whom advocates an actual speaker (reactive) load!   :icon_biggrin:

No, at this point I step back and ask "Who is Gerald's audience?"

Guys who have test gear and know how to use it already know more than Gerald is teaching. A guy just getting into amp-tinkering seems like the target audience. This guy has an amp but little test equipment.  He's probably lucky to have an oscillator at all, and probably no dummy load. So just measure across the speaker terminals. It works.

Friendly Dare: Try listening to a full-power 1kHz sine wave when checking the output power of a 100w amp. Then tell me how many milli-seconds it takes you to decide that sucks, and that you should invest in a dummy load for power measurements.

I did a fair amount of multi-track tape machine alignment when I was in school for audio engineering (like at the start of every recording session). Listening to a 1kHz tone will make you want to put an icepick through your eye. Listening to it at 50w or 100w will make you swear off power measurements without a dummy load.

Just try it.  :laugh:
Title: Re: Measuring output power?
Post by: jjasilli on December 29, 2014, 07:05:20 pm
Listening to it at 50w or 100w will make you swear off power measurements without a dummy load.


That's the Con's alright!   :thumbsup:
Title: Re: Measuring output power?
Post by: PRR on December 29, 2014, 11:42:37 pm
> Did they test thousands of frequencies?

No. Impossible and "obviously"(?) not necessary. Why would a simple broad-band amplifier pass 456Hz but not 457Hz? It isn't smart enough to do anything so refined.

> Into a resistive load, or a speaker load?

Assuming we test at the 8 Ohm tap, then into *8 Ohms*. Something which is a KNOWN resistance over any broad range of conditions (level, frequency) IS a resistor. Loudspeakers are not resistors (let's avoid that can-o-worms for a moment).

These amps have several taps. By ideal transformer therory, we get the same power at any tap if loaded in the design resistance. In real life we may see small differences, but SMALL. It will surely make 15 Watts in 4 or 8 or 15 or 500 Ohms. It is probably a 20 Watt amp; good PA amps use a large CYA factor to allow for tolerances and rounding errors.

An audio power amplifier has a Flat Band in the middle of the audio spectrum and Roll-Offs at high and low frequency. The choice of roll-off often depends on Price. Note the low-price AU-32 claims 75Hz, the high-price AU-33 claims 50Hz. We could buy tube amps rated for full power to 20hz or lower (shaker-table amps), but they cost and weigh more.

Guitar amps have to go to 80Hz pretty-much. Some (say a $400 Fender) maintain full power much lower and cleanly. Some (say a $40 Kent) get pretty crappy at full power anywhere near 80Hz. There's a Right Way and then there are compromises with customers' budgets.

> Into a resistive load, or a speaker load?

Speakers are complicated contraptions. And all practical speakers face fundamental problems. Any air-pusher is too small or too heavy (invariably both) to cover the audio band. They have to balance 2 or 3 reactances against each other to approach wide-range operation. Impedance seen at the terminals is usually ALL over the place as these reactances wrestle each other.

The saving grace for dynamic speakers is that the copper resistance is in series with everything else. So there is a *minimum* impedance which is reliable and can be designed against. Most power sources (including audio amplifiers) can be designed for a load which is not-less-than some specified Ohms.

The speaker designer (not the amp designer) is responsible to ensure the speaker gives good results even while its impedance varies higher than nominal. This actually works-out nice. At bass resonance the impedance goes up to 50 Ohms. The power sucked from an 8-Ohm tap may be 8/58 or about 1/8th of the rated power in 8 Ohms. The amp is happy delivering 1/8 full power. The speaker input is less but at resonance the speaker self-efficiency is very high, easily 16% on a nominal 2% efficient speaker. So the acoustic output is similar on or above bass resonance.

The AMP designer works to resistor loads. Oh, to cover his butt he should consider other likely loads. But comparisons are done on resistor loads, because they are valid-enough for most loudspeaker loads. If a loudspeaker causes a problem, blame the speaker designer.
Title: Re: Measuring output power?
Post by: Jim Coash on December 30, 2014, 05:32:27 am
I agree that finding and sticking to a "method" of measuring power is a good thing provided you remember to take any numbers with a grain of salt.  My method is to look for a number that specifies all of the terms.  A few years ago I needed a small amp to drive a set of KEF speakers I installed in my Jacuzzi room for my wife, primarily.  There was no room for a conventional receiver or integrated amp.  I bought a Chinese unit not much larger than a paperback novel with a pair of mounting brackets and a wall wort A/C supply.  The box clearly says in large letters "180 Watts X 180 Watts".  Patently ridiculous.  Maybe 12 watts/channel at 1000hz.  The problem I dealt with every day at my audio store was people making comparisons based on printed "specs" or what an appliance store salesperson told them.  Often someone would tell me that they could get an XXX watt amp for half the price of the one I was demonstrating.  When I asked them if the amp actually sounded any better (or even louder) than mine they often would say that they hadn't even listened to it.  They were simply buying on misleading information, not sound.  The Carver or NAD amp I recommended appeared to cost more, until you brought the actual power rating into perspective.  An NAD basic receiver at $300 was rated at 25 watts/channel/@>.1%THD/both channels driven/at any frequency 20 to 20K.  They even specified at least 6 db of headroom.  That means that the amp can cover 100 watt peaks for musically significant periods of time and those amps were stable into less than 2 ohms!  Speakers are a very complex load and music is nothing like sine waves.
Yesterday my son and I connected two of my recent speaker projects for an evaluation.  For an amp we used a rack with a Hafler Hellraiser
tube guitar preamp run through a DOD compressor into an E/V 1.5 power amp.  My Fender Dual Showman "clone" box with a pair of EVM-15 speakers is awesome.  The old Ampeg cab I bought for $50 on eBay and re-built to eliminate the place for the missing amp chassis and fitted with an E/V-15G recone I bought for .99 cents and fixed for $75 sounds amazing.  The E/V SRO-15 that came in that box will go into a new cabinet I am nearly done with that will be my Stevie Ray Vaughn box.  Just like he specified for his Fender Vibrolux.  What point is there in discussing power?  It is nearly impossible to make any valid comparisons given all the variables.  Jim
Title: Re: Measuring output power?
Post by: HotBluePlates on December 30, 2014, 03:44:09 pm
... The problem I dealt with every day at my audio store was people making comparisons based on printed "specs" or what an appliance store salesperson told them.  ...  What point is there in discussing power?  It is nearly impossible to make any valid comparisons given all the variables.

The point within this forum is that by & large, the folks here will be building an amplifier from scratch. Possibly a completely original design. There are no printed specs, nor salesman.

[The exception is building a copy of a known-plan. But in that case, the power output is largely known. And there's very little performance difference if the claimed "40w amp" turns out to be 30w or 45w in actual use. Known-plans have also taught most builders that 100w from a pair of 6V6's is impossible, and what the likely power output will be.]

In that context, they may wish to evaluate their new design against previous efforts, as a way to evaluate any new changes. If the builder cares about the validity of the numbers, they will pick a procedure to be replicated with every measurement; control of the process is absolute, because they will be the one performing the process.

And a simple measurement might be preferable to looking at a pair of push-pull 6V6's and saying, "Ehh.. something between 10-24 watts." The builder should know enough if they're creating their own design to rough-in the numbers at least that much. It should also be obvious to them that if they measure 40w output there is a problem in their measurement; if they measure 4w, they should know there is a problem in the measurement, or in some failing in the amp's design or construction (which would be handy information for future designs/builds).
Title: Re: Measuring output power?
Post by: jjasilli on December 30, 2014, 10:56:42 pm
What point is there in discussing power?  It is nearly impossible to make any valid comparisons given all the variables.  Jim


We have lost track of the original question posted in this thread, about the Gerald Weber method.  There is nothing wrong with measuring the actual output voltage of particular amp into the speaker with which it always, or often used.  And using that speaker's nominal impedance to calculate watts.  The fact that there are other methods, or that other methods are used by testing laboratories or R&D dept.'s, does not invalidate this method.  Inquiring minds want to know!  :icon_biggrin:


What point is there in censoring power out of consideration?  Do you want a bedroom amp? living room amp? stage amp?  Do you want the sheer power to affect the tone of the guitar on stage per Jimi Hendrix? 
Title: Re: Measuring output power?
Post by: jjasilli on December 31, 2014, 01:44:57 pm
It is impossible to get a wrong answer by doing a test, any test, correctly.  The fact that different test methods produce different results does not invalidate a test method.  The differences in test results can be accounted for scientifically. 


The Fender BJr revD schematic states 10.25V rms output into an 8 Ohm resistive load; 1KHz input signal @ a specific mV rms, with controls @ certain positions.  5% THD.


Presuambly:


* if we change control positions we'll get a different output voltage
* if we use a reactive load we'll get a different result (a reactive load doesn't have to be a speaker.  It could be a speaker simulator circuit; or a speaker motor like a Weber Mass dummy load)


No test is invalid.  Different results can be accounted for if we know how the test was done.
Title: Re: Measuring output power?
Post by: HotBluePlates on December 31, 2014, 04:27:04 pm
The Fender BJr revD schematic states 10.25V rms output into an 8 Ohm resistive load; 1KHz input signal @ a specific mV rms, with controls @ certain positions.  5% THD.
Blues Junior Rev D Schematic (http://el34world.com/charts/Schematics/files/fender/Fender_BLUES_JUNIOR_REV_D.pdf)

Correct. This measurement was given as a reference for a full-power test of this amp, for a repairman's reference. The Output Test note gives the specific conditions.

Presuambly:

* if we change control positions we'll get a different output voltage
...

No test is invalid.  Different results can be accounted for if we know how the test was done.
These statements are correct.

Look at the input jack on the schematic; it says, "For AC Voltage Measurements, Apply 1kHz Test Signal" and then indicates a 10mV signal at TP1 (the input jack). All the subsequent voltages in the ovals are the resulting voltages at those test points, with 10mV at TP1 and with the controls as specified in Note 2 at the bottom left of the schematic.

There is a clue to all this: if you look at TP16 (output tube grid) and TP18 (output tube plate) you'll see similarly-small voltages... Only ~1vac drive to the output tubes (when a peak voltage closer to the bias of -10.7v would give full output power) and only ~41vac at the output tube plate. As a result, the output at the OT secondary is appropriately-low (so TP20 does not represent full-power output, but that was known by the math and Fender's Output Test note).

I going to state an opinion, without watching Weber's  video.  IMO, Weber is not correct,  Look at the various schematics of Fender Music's Blue's Jr.  schematics.  it gives an A/C voltage on the O/T's secondaries of some what less than 3 volts.  Using the 8 ohm resistive load and the Ohm power calculation, you don't come up with 13 watts the schematic presents as power output, you need between 10 and 11 volts to come up the the stated wattage.  Bottom line, unless someone provide me with Weber's credentials, I'll take Fender Music information as being more credible.

Standard Response (http://el34world.com/Forum/index.php?topic=16366.msg161078#msg161078)
Title: Re: Measuring output power?
Post by: HotBluePlates on December 31, 2014, 05:43:05 pm
Gerald Weber shows you how to do a Quick and Easy Wattage Check (https://www.youtube.com/watch?v=1b2jQWK8xlQ)

Standard Response (http://el34world.com/Forum/index.php?topic=16366.msg161078#msg161078)
Title: Re: Measuring output power?
Post by: darryl on December 31, 2014, 06:05:50 pm
Contributors to this thread have provided their opinions on whether 1kHz or a 400 Hz single should be used.  I don't know if the signal affect the power reading on a resistive load, but my guess is no.

If an amplifier's output power measured at 1kHz is significantly different to that at 400Hz, either the amplifier or the test method has a serious problem.
Title: Re: Measuring output power?
Post by: 2deaf on December 31, 2014, 09:44:05 pm
You know . . . Jerry tells you how to do it at the start of the clip.  He never says that the text books are wrong and it's kind of funny how he mentions O'Scopes and function generators as the camera pulls back to reveal both right behind him.  He doesn't finish telling you his method or what the significance is of whatever number he comes up with -- you gotta buy the DVD.  You have to ass*ume (as PRR put it and as Felix Unger expounded upon) if you think that he is going to divide by the nominal impedance of the speaker to derive the output wattage.

He says that the voltage is about 5 volts right before fade out, but I saw 6.867 go by.  The wattage at 6.867 is approximately twice the wattage at 5.  Is the amp even maxed-out?  It doesn't sound like it to me.  I can't really criticize the guy from this clip since I have no idea what he is going for.  I'll tell you what, though.  He can take a helluva shock and come back with a grin.
Title: Re: Measuring output power?
Post by: JB on January 01, 2015, 07:06:35 am
I've always thought 1KHz was used for measurement as it's the nearest nice decimal number near the middle of the speech band used in telephony - 300Hz to 3KHz band limited telephone circuits.  In my field of broadcast engineering 1KHz is used for all circuit line-up's, reference tone on TV test cards, mixing desk built in reference tone etc. etc.
 
Title: Re: Measuring output power?
Post by: HotBluePlates on January 01, 2015, 09:38:57 am
I've always thought 1KHz was used for ...

Your explanation sounds perfectly reasonable; thanks for offering your expertise.

For the purposes of this thread, the frequency is probably a non-issue (if it is an issue of contention, a good sweep oscillator is all that's needed). Instead, the question of 1kHz vs 400Hz is only being raised repeatedly by someone notorious for trolling on this forum.
Title: Re: Measuring output power?
Post by: jjasilli on March 08, 2015, 01:22:22 pm
Blundered into some interesting info here, though geared to hi-fi: http://www.americanradiohistory.com/Archive-Electronics-World/50s/1959/Electronics-World-1959-11.pdf (http://www.americanradiohistory.com/Archive-Electronics-World/50s/1959/Electronics-World-1959-11.pdf)


This addresses many of the issues in this thread; how & why tests are done in certain ways; and how to interpret test results.



The Nov 1959 Issue of Electronics World:  Harmonic Distortion, p. 72; and Measuring Your Audio Output Power, p. 92. 


Thanks to PRR for posting the americanradiohistory.com website in another thread.  I've been going through the issues as I get the chance.
Title: Re: Measuring output power?
Post by: shooter on March 08, 2015, 04:00:09 pm
I ran into an anomaly when "spec-ing" my SE build, I used a 10ohm load as usual @ 1K, but then thought what the hell, wife is gone, got ear muffs so I did the output @ speaker and it did change.  It made sense since I changed the "wanted" load of 8ohms to 10.  The oddity though was both loads at max clean signal came in about 10.8Vac rms.  Times that by 1.414 and that should be close to max, and it was for the resistor but the speaker yielded 23W. double checked, same.  Donno what it means, or care, my standard is the 10ohm resistor @1k then all my amps are apples to apples for all MY amps.
Title: Re: Measuring output power?
Post by: HotBluePlates on March 08, 2015, 09:24:29 pm
Blundered into some interesting info here, though geared to hi-fi: http://www.americanradiohistory.com/Archive-Electronics-World/50s/1959/Electronics-World-1959-11.pdf (http://www.americanradiohistory.com/Archive-Electronics-World/50s/1959/Electronics-World-1959-11.pdf)

This addresses many of the issues in this thread; how & why tests are done in certain ways; and how to interpret test results.

The text of the article on distortion says, "In the early days of hi-fi, it was common to take harmonic distortion measurements at only one or two frequencies around the middle of the audio band, commonly 400 or 1000 cps." The article doesn't say why, other than that test equipment had improved.

Below is an HP 320A "Distortion Analyzer". Really, the device is an attenuator which can accurately reduce the signal at the input terminals by a specific number of dB set by the switches, and a filter which can null out either 400Hz or 5kHz.

(http://www.kennethkuhn.com/hpmuseum/hp320a.jpg)

The method for measuring distortion at the time was to apply a test signal to the circuit under test (at either filter frequency) and measure the signal level at the output with a separate meter. Then you'd kick in the filter to eliminate the single test frequency (at the output) and measure everything else left over, yielding a "THD + Noise" figure. Part of the test setup was to tune the frequency of the oscillator until you had the best null when applied only to the filter and nothing else, because you wouldn't trust the oscillator and the filter were calibrated well enough to each other to agree on what "400Hz" was. You might also need to do this setup just to measure how much distortion your oscillator had prior to being applied to the circuit under test.

Kinda clumsy, and you needed at least 2 other pieces of gear besides the "distortion analyzer" just to make a distortion measurement. But if you already had a meter and an oscillator, it was a good way to add a distortion measuring capability. The bulk and cost of the system at the time made having multiple frequencies for filtering cost-prohibitive and impractical. See the image below for an example of this test setup; the item 2nd from left is the amplifier actually being tested.

(http://www.hpmemoryproject.org/pict/wall_a/amp_test_50s.jpg)

HP wound up combining all the functions in a single chassis in the 330B, below. There was an oscillator circuit which was tuned by the center knob to a frequency displayed in the center window. Also tied to that knob was a tunable filter which nulled out the single frequency produced by the oscillator. Now you could dial to any frequency in the range of the analyzer and measure THD+noise. There was an output to the circuit under test, with the output of that circuit returned to a set of binding posts which fed a calibrated attenuator and a voltmeter. Between the two, you could measure THD and noise in the form of "so many dB below the desired signal."

(http://www.hpmemoryproject.org/pict/wall_a/330b_left.jpg)

It took yet more time (and transistors) before the HP 302A Wave Analyzer was produced (below). This was a selective voltmeter design that let you measure the amplitude of a single frequency (at least within a fairly narrow pass-band), so that you could apply a 100Hz test signal, for instance, and find out the amplitude of the resulting 200Hz, 300Hz, 400Hz, 500Hz, etc harmonics, and be able to know exactly how much of each harmonic was being generated apart from noise.

Point being, there are all kinds of inter-related reasons for conducting tests the way they were once done, some for good technical reasons and others because of limitations of existing test equipment at the time.
Title: Re: Measuring output power?
Post by: jjasilli on March 09, 2015, 09:23:06 am
Been reading up on this including articles on this site: http://sound.westhost.com/projects.htm (http://sound.westhost.com/projects.htm)  Now I don't remember which bit of info comes from which article.  Anyway it seems that for human beings the heart of all musical information comes from the freq range of about 300 - 3000Hz.  Even deep bass notes may be implied from their harmonics in this range. Confirming many posts in this thread, 1000Hz is conveniently right in the middle of that range.  400Hz is a good distance below yet still in that range.  Deeper notes are expected to give worse THD, so this gives more info.


THD = total harmonic distortion.  It lumps it all together and lacks specifics: like which order of harmonics; at what frequency; etc.  But, it is still useful info.  If a reputable manufacturer states, say, 2% harmonic distortion @ 40W RMS from 30 - 15,000Hz, this means that's the worst you'd expect over that entire range.  Hence you can expect THD to be dramatically lower @ 1000Hz.


Other points.  Typical volt meters are for low freq AC; and don't measure VAC well at musical frequencies.  A true RMS meter would be  needed.  The tests -- THD and Watts -- are done purposely with a non-inductive resistive load, to eliminate the vagaries of reactance.  The load value should = the amp's rated ohm output tap.  If the resistor gets hot its resistance value increases, throwing-off the measurement.  Hence the resistor should be rated for 5X the expected power in watts.  A lot of this seems like overkill for guitar amps, but it's good to know.
Title: Re: Measuring output power?
Post by: HotBluePlates on March 10, 2015, 07:15:39 pm
Other points.  Typical volt meters are for low freq AC; and don't measure VAC well at musical frequencies.  A true RMS meter would be  needed.

"True RMS" doesn't tell you about the frequency range of your meter. I don't know if you meant to imply that, or if it was just 2 separate statements.

The article was probably talking about old analog voltmeter movements, like a 1000Ω/volt (1mA) movement. Today, your multimeter very likely has a much wider range of a.c. measurement. My Fluke 87III doesn't seem to droop until couple-hundred kHz. HP made some a.c. voltmeters good to 400kHz and beyond. Point being, you have to know the capabilities of your particular equipment to know if this is a pitfall.
Title: Re: Measuring output power?
Post by: PRR on March 11, 2015, 09:18:47 pm
> a 10ohm load as usual @ 1K,
> I did the output @ speaker and it did change


The speaker is everything except 8 Ohms. It is probably 50 Ohms at 90Hz, may be 6 or 9 Ohms around 400Hz. A typical guitar speaker will be rising by 1KHz, possibly 12 Ohms.

In many guitar speakers, 20 Watts for many seconds will hot them up enough to raise the copper resistance. You can often double the resistance by abusing it until the smoke comes out (actually modern glues don't even smoke good).

Get a big 40 Ohm 10 Watt resistor to put across your 10 Ohm, for a true 8 Ohm load.

> Times that by 1.414

I do not understand this math. If you already found "max clean signal", what are you multiplying for? And where did 1.414 come from? If you alternately want to know the GROSS OVERDRIVE power output, run it up into Gross Overdrive. The problem is that the "RMS" of a severely bent wave is not easy to measure. If the overload is nearly Square, you may measure peak-to-peak and do the math for a square wave. Some meters read RMS direct, despite somewhat bent waves. An Averaging meter will read a Square fairly well, and a dumb passive meter was used at many early g-amp labs.
Title: Re: Measuring output power?
Post by: shooter on March 12, 2015, 08:59:43 am
Quote
GROSS OVERDRIVE

That's sorta what I was going for, I think I got that number here for "ball-parking" max distorted amp power.  I did dime the amp and that's where my math and reality went separate, math showed 16ish, reality showed 23W.  My 10ohm 250W is what I have on hand but I think I can scrounge a || 40 for 8ohms.  The main thing for me is to measure everything the same way every time....even if it's wrong, it's consistent :icon_biggrin:
Title: Re: Measuring output power?
Post by: octal on March 12, 2015, 04:12:18 pm
Just for fun, here are some scope shots and voltmeter readings from a little EL95 push-pull amp I built. First shot is clean, low power, second shot is just before real clipping, third shot is a bit of clipping and the last shot is dimed, squarewave city.
Title: Re: Measuring output power?
Post by: octal on March 13, 2015, 05:35:03 pm
HP sinewave generator into amp's input, 400Hz signal. Amp is loaded with an 8 ohm, non inductive dummy load. One channel of 'scope is connected to the input of the amp, the second channel is connected to the speaker output. (I like to do this so you can see how the shape of the output sine wave compares to the input.) It can create some ground loops testing this way though.

Weber's method is next to useless, IMO. You can get a decent secondhand sinewave generator, OR a test CD, OR download a file to an iPod and feed in into an amp... there's no excuse for using a guitar as a signal generator for basic amp checks other than laziness.