Hoffman Amplifiers Tube Amplifier Forum
Other Stuff => Cabinets-Speakers => Topic started by: nateflanigan on February 17, 2015, 06:27:13 am
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I blew a speaker or two in my Ampeg 610 cab. It's sort of an odd set up, 6 ohm speakers, three series sets of two wired in parallel. I'm having a hard time finding the 6 ohm speakers. Out of curiosity, I was thinking about upgrading all the speakers (BIG expense, so probably not). If I used 4 ohm speakers wired the same way I'd end up with a 5.3 total impedance, which probably isn't too much of a problem. But, I was wondering if I did sets of a 4 and an 8 in series to get the 12 ohm blocks for parallel I'd end up with a 4 ohm total. That seems like it's flying in the face of convention though, since I've never seen that before I'm guessing it's no good to have mismatched drivers. Any insights?
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If I used 4 ohm speakers wired the same way I'd end up with a 5.3 total impedance
No, that would be 2.67Ω.
I'd use all 8Ω speakers which will give you 5.3Ω.