Hoffman Amplifiers Tube Amplifier Forum
Amp Stuff => Tube Amp Building - Tweaks - Repairs => Topic started by: kagliostro on March 09, 2017, 03:27:26 pm
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A simple VVR we use is this
(http://i.imgur.com/BubXqJy.jpg)
The 47k resistor set the lower voltage that can be reached
if we want we can add one other resistor between B+ and the pot to drop the higher voltage that can be reached rotating the pot to the max
(http://i.imgur.com/Bh8y8Oq.jpg)
I don't know how to establish the value of the added resistor, so I've think to the sum of resistor + pot as a resistor voltage divider
I did a bit of math and to me seems that around 420K will be a good value for that resistor
(assuming 350V B+ and 250V the max voltage to have on the output)
Can I consider that as the right way to calculate that resistor ?
Thanks
Franco
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That's the right answer (actually 418,800Ω), so I assume you did it correctly.
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Many Thanks Steve
Franco