Hoffman Amplifiers Tube Amplifier Forum
Other Stuff => Other Topics => Topic started by: tubesornothing on September 16, 2009, 02:50:26 pm
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I have some old 6V mountain bike lights with dead lead acid batteries. I want to cheap out an ressurect them, but use my 18V LiIon drill batteries. I am figuring out a way that I can drop the voltage without too much waste. Here is what I have looked at:
1. use a series resistor - too much power waste
1. use a zener - too must power waste?
3. regulator - I think 18V into a 6V regulator will cause too much power waste
4. DC-DC converter - good idea, but the cheapest is $80
5. Run the two 6V light in series and overvolt them - hmm, I don't want to fry the lights.
Any other suggestions?
thanks
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three lamps in series - no waste.
with two lamps 6V wasted - or the power of one lamp.
with one lamp 12V wasted - or twice the power of one lamp wasted.
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I only have two lamps though... I don't really want to spend more money, if I can help it.
I did find a 6V regulator that will take up to 20V input with a 7A output for about $14 (kinda pricey) I suppose I could just get a couple of 6V 3A regulators, it might be cheaper. Not sure, but do regulators have much waste heat with a large potential of voltage?
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OK, Wikipedia says linear regulators or inefficient cause "regulates the voltage by burning off "unwanted" voltage as heat" - not what I want.
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Well, maybe the 2N3055 transistor and a pot for bias would be cheaper than a regulator etc. The transistor could heat sink off the bike someplace (??)
Sorry....just another brain fart :grin:
Oh yeah, once the correct R value was found for that voltage and load, a resistor could replace the pot ( that's two brain farts)
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I think I would be in the same boat - offloading the volateg difference as heat. To much of a waste of precious power.
After a lot of looking into this, I think I will switch to LED lights. Doug and others have put out a lot of info on how to roll your won. There are also some inexpensive DC-DC converters, so I can leverage my drill batteries.
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Two 3.6 lithium ion 2500mah batteries are $6.83 with free shipping
http://www.dealextreme.com/details.dx/sku.29030
7.2 volts total in series = 2500mah
4 is series/ parallel = 4800 mah battery pack
I am guessing you are trying to run Halogen bulbs?
They might not take 7.2 volts.