typically in a single tube A1 design, you run Pdiss @ 90% of max. rating. 6V6GT power rating in A1 service is 12W max. 11W is close enough to 90%, so we'll use that.
to solve for Rload, we know what Pdiss max is, but... what's is your B+ to be? 300? 350? 400?
determine that, then apply formula. Va
2 x Pdiss. (11W in our 6V6 case).
backwards... example you have a tranny, it's 9K into 8ohm. i want to run 6V6GT, A1 single tube with an 8 ohm speaker load - how much B+ (Va) do i need where 9K load is optimum? consult ohms law
pie chart. we have R we have P we need to solve for V.
sqrt p x r = sqrt 9k x 11W = 99K x sqrt = 314.6V
this is a simplistic approach but it gets you in the ballpark and works.
in reality, if running cathode / auto bias, you would subtract Vk from Va then that would actually what you'd use for value of "V". you're solving for the power dissipation of the tube only - not the tube and the cathode resistor. in other words, power dissipation of tube is the voltage measured from anode to cathode * the current flowing through the tube; the voltage measured from anode to cathode usually called Vtube. if you were to run fixed bias, there is no cathode resistor so then Vtube is measured from anode to gnd.