Many thanks
HotBluePlatesI mean there are tubes generally meant for use in RF transmitters which have graphite plates instead of getters
Now I understand, I've seen those big tubes redplating in RF equipment
If you need a certain amount of clean power output, then there is a "right answer" for OT impedance and supply voltage given that there are only so many different transformers to pick from. So you pick the OT for the power you need and supply voltage you have, then choose output tubes which can deliver the current needed.
And if is correct to chose the tubes looking to the PT and OT, often we want to start from a given tube, and we base the choice of the transformers (PT & OT) using the data the tube requires we find in the datasheet
this is, as you say, for max performance, using all the tube ability to give power
if I remember well
PRR told
Voltage / current = impedance(as example 400v / 0.04A = 10.000ohm impedance)
If maximum clean power is not important, you can pretty much use any primary impedance with any tube while realizing that power output will either be a little or a lot less, and distortion will be a little or a lot more.
So we can use an arbitrary impedance and we can expect a lower power and more distortion
that I think will be due to the impedance mismatch from the tube and the OTHaving a given tube that can express his better performance at a particular voltage and current (one option for QQE04/20 say 425v | 0.026A | Bias -60v = Wo 2 x 16W
http://www.r-type.org/pdfs/qqe04-20.pdf see page #5) of course there is a better suited OT primary impedance for this voltage and current values
If you're not trying to wring every last watt out of the circuit, OT impedance isn't critical.
If I want to have only Wo = 2 x 5W instead of 2 x 16W is correct to say I can:
lower voltage keeping current the same (Bias voltage used to control the current)
lower current keeping the Voltage the same (Bias voltage used to control the current)
lower Voltage and current (Bias voltage used to control the current)
At this point, if what I told is correct I've a voltage and a current to be used as to establish an OT impedance
the question, if possible to be presented, is:
is better to apply the previous formula
Voltage / current = impedance to the voltage and current I've chose to use or it will be better to use the "standard" impedance given by the data on the datasheet for the max performance
If I've an existing Power Amp with a certain OT and I use a VVR to decrease power (assuming I decrease Va - Vg2 & Bias) what I know is that with the same OT primary impedance the reduced performance in Wo of the tubes will have the same tone with less headroom and the tube will act as a smaller tube (I can obtain distortion/compression from the tube at a lower level, as if I was using a 5W power tube instead of a 15W power tube)
So, hard question, is better to use the OT primary impedance given by the "max performance" in the datasheet or the OT primary impedance using the arbitrary chosen voltage and current ?
K
p.s.:
Jazbo8, you posted when I was writing my replay, I've seen the plot, but this didn't help me to understand what is better to use to compute the OT impedance in this particular instance