I'm assuming that there is a "stable" ratio between plate and screen voltages when working with datasheets.
So, the datasheet offers an operating condition with 315 plate volts and 225 screen volts. If I have 330 plate volts, then 236 screen volts ...
We could "extrapolate if we had only an example condition or two, but we have curves. So let's just use the curves. It sounds like I need to show how I used the data sheet to derive the answers I wrote earlier. So let's look at a
6V6 data sheet.
2 things control plate current:
1. G1 volts, which we usually call "bias volts." It's the voltage from grid-to-cathode.
Since you are going to cathode bias, the grid is tacked at 0v (via a grid-leak resistor), and the cathode is positive by the voltage-drop across the cathode resistor.
2. G2 volts. This is the voltage from screen-to-cathode.
Changing plate volts barely move plate current, but screen volts definitely changes it (just less than G1 volts). So moving the screen to a higher voltage will bring up the plate current.
Design is iterative. I'm gonna start out assuming "320v" plate and "250v screen" mainly because the data sheet has curves drawn for 250v screen.
1. Let's assume this 6V6 will idle at 100% plate dissipation (of 12 watts). 12w / 320v = 37.5mA. So put a dot at "320v, 37.5mA" (this seems to land right about -15v G1 bias) and draw a line from it to 37.5mA x 2 = 75mA on
the plate curves for 250v screen. That's the upper-graph on Page 3 of the linked data sheet. (Open the image in a new tab to see full-size)

2. Single-ended amps must be Class A. This implies the plate current will peak at 2x idle current on one side of the signal cycle, and drop to almost-zero-plate-current on the other side. Your chosen OT has primary impedances of 5kΩ and 7kΩ available. The peak plate current
change of 37.5mA will create a voltage-drop across the OT primary and pull the plate voltage momentarily low, so we need to know whether the tube can support the plate-voltage-change.
A. 37.5mA x 5kΩ = 187.5v -----> Plate pulled down to 320v - 187.5v = 132.5v at 75mA (Red dot)
B. 37.5mA x 7kΩ = 262.5v -----> Plate pulled down to 320v - 262.5v = 57.5v at 75mA (Green dot)
Plot both these points on the same set of curves, and see whether the tube can manage the plate current
at that screen voltage.
The Red loadline (7kΩ) maximizes plate-voltage-
swing, so it delivers higher output power. And we see that the tube could have pulled the plate down to 35-40v without issue. So we know the 7kΩ loadline is closer to an "optimum load."

3. If we look at the dashed curves on the graphs above, they represent screen current for a few different G1 voltages. The most-negative dashed curve drawn is for -12.5v bias, and using the scale on the right side we see screen current at our idle plate voltage will be something like 3-4mA. We could try to plot another curve of our own for "screen current over the signal cycle" but it appears that it won't peak above 18mA; we tack G2 to a filter cap that will supply some of this peak current.
4. Now we have some parameters: 320v plate, 250v G2 so 320v - 250v = 70v dropped across the screen dropping resistor. 4mA screen at idle plus 4mA preamp is 8mA, so 70v / 8mA = 8.75kΩ ----> not a standard value, so "8.2kΩ 3w" is "close enough."