"Where did you get it from?
What's on the other side?"
]||[----Black\
]||[ (99) \
]||[----Blue (122)
black--------]||[ (23) /
]||[----Red--/
green--------]||
]||
yellow-------]||[----Red/Y-\
]||[ (23) \
light yellow--]||[----Blue/Y (112)
(faded ]||[ (89) /
orange???) ]||[----Black/Y/
use caution!
1) tie off all the leads to some barrier strip(s).
2) connect the red and red/yellow together.
3) with a lamp limiter, apply 120V/240V (or whatever the line V is where you live) to the black and black/yel.
4) measure and record VRMS from black to black/yellow (yes, the line voltage ;) )
5) measure and record VRMS from black to green, then black to yellow, then black to orange.
post results. or, calculate turns ratios yourself (Vpri)sq / (Vsec)sq = TR. now multiply TR by the load resistance you would apply to secondary and that will be the primary impedance.
ex. i have a sears silvertone 1484 OT i need test:
i apply 120VRMS to the primary (plate to plate) blue to brown leads and i measured the following:
1) black to red/yel = 3VRMS
2) black to yel = 3.62VRMS
calculate:
1) for primary (VpriSq) = 120*120=14400
2) for secondary black to red-yellow (VsecSq) = 3*3=9
3) divide pri/sec = 14400/9=1600
4) now pick a load - i want 4 ohms on the blk/red sec taps so then 1600 * 4 = 6.4K:4 that confirms that this is likely a 6.6K:4ohm transformer ratio.
how about the 2nd secondary (black to yellow)? ok, 3.62*3.62=13.1 then 14400/13.1=1099. now we know it's a probably a 6.6K part but lets say we apply 6 ohm to this tap, so then we have 6.5K:6 transformer ratio, or with an 8 ohm load you could make it 8.8K:8.
on a footnote, it IS a small OT for a pair of 6L6GC even if they are running in cathode bias. maybe that's why we see so many 1484 silvertones with a replaced OT.
--pete