... Design goal was maybe 7 Watts. (There may have been a 14W model at a higher price.) You shop around for a pair of tubes to do 7 Watts.... some oddballs, but you keep coming back to 6V6 working well below what they "could" do. (Especially convenient if your factory stocks 6V6 for a 4W SE job and that 14W PP job, and gets the quantity discount.) ...
Yep. They coulda used a 6K6 for a 7w amp, as that's an 8.5w tube. But if the company make 8-10 models which use a 6V6, and only need the 6K6 for a model or two then it's probably cheaper just to use 6V6 everywhere.
How should I bias it? Does 23mA @ 201V seem cold for 6V6s?
You shouldn't "bias" it. The circuit has a cathode resistor for the output tubes, so plug the tubes in the sockets. Biasing done.
190plate guesstament(B+ -cathode)
50mA * 190 = 9.6WPdis
or your 201*.05 =10WPdis @ 70% = 35mA
220 ohm cathode resistor @ 10.25V (10.25/220=0.0466)
(0.0466/2=0.0233) per tube @ 201V(211V-10V)
So 23.3mA X 201V = 4.68Watts per tube
4.68W is 39% of the 6V6s 12W rating Is that right? And does that seem low?
At a B+ of ~210vdc, this is almost certainly a class A amplifier. So "70% rule" is out the window.
+1 to what everyone else said regarding not needing to operate the output tubes to their limits. Which reinforces something I've said before about idling at a specific % of plate dissipation being false rules (except that you usually don't want to exceed 100% dissipation at idle).
Further, consider that
we might want distortion in a guitar amp, but distortion in a record player is undesirable. If you're idling at ~4.7w with 10.25v of bias, then you should know that idling hotter will require a smaller bias voltage. 8v or 5v or whatever.
But you should also know that tubes begin drawing grid current when their bias voltage is roughly in the range of 0-to-1 volt. Grid current equals onset of severe distortion, so if you biased your output tubes to 5v you might only be able to get 4v peak of signal voltage to drive the output tubes. But idling cooler, around 10v, allows a bigger driving signal before onset of distortion (as much as 9v peak or so).
The idle current is probably also sized to match the bias, expected output power, and OT primary impedance. Said a different way, 23mA at idle is perfect if you only need the output tube current to rise to 43mA (a 20mA increase) and fall to 3mA (a 20mA decrease). What if the output tubes could do that 40mA peak-to-peak swing with less than 18v peak-to-peak (9v peak) input signal? And what if the 6V6 needs ~50v left plate-to-cathode during the peak current swing?
21v - 50v = 160v peak plate voltage swing.
43mA (peak plate current) - 23mA (idle plate current) = 20mA peak plate current swing.
160v / 20mA = 8000Ω (look familiar for 6V6 output transformers?)
Output Power = (peak plate current * peak plate voltage swing)/2 = (0.043A * 160v)/2 = 3.44 watts
I know I can't dime a Champ-sized amp in my apartment without pissing off neighbors. I'm sure I wouldn't want my kid's portable record player to be louder than 3-4w of clean output power (maybe not even that much, considering my son is driving me crazy with some of his t.v. shows...).