The only other thing I can think of is that the OT is one that has a 4 ohm and 8 ohm tap , I use an 8 ohm speaker and was told by Hotplateblues that I should connect the 2.7k ohm NFB to the 4 ohm tap even though the speaker is an 8 ohm speaker on the 8 ohm tap and this would show the OT the proper NFB resistence. At first I just took the lead from the 4 ohm OT secondary tap and wired it direct to the 4.7k NFB resister , after I added the 4 ohm tap jack I still used the 4 ohm OT secondary tap for the NFB resister only off the jack rather than direct off the OT 4 ohm wire. . Champs were 4 ohm only as you know. I found this on Aiken amps.
"The series feedback resistor, in conjunction with the resistor to ground, determines the amount of voltage being fed back. If you want to feed back more voltage, you make the series resistor smaller, or the shunt resistor larger, or you use a higher impedance tap on the output transformer.
The actual resistor values used in the feedback attenuator aren't that important, as their ratio determines the amount of feedback. The shunt resistor value is usually fixed by the phase inverter design requirements, and the series resistor is then sized according to the desired amount of feedback, given the voltage available at the output. Note that Marshall typically uses 100K/5K attenuator, while Fender uses a 820ohms/100ohms. You can get the same attenuation from a 10K/500ohm pair as you would from a 100K/5K pair. In addition, if you were using a 100K/5K attenuator running from the 16 ohm tap, you would get roughly the same amount of feedback if you used a 47K/5K attenuator running from the 4 ohm tap. Note that the tap voltage is not linear with respect to the impedance, it varies linearly with the square root of the impedance. That is, the voltage on the 8 ohm tap is not half the voltage on the 16 ohm tap, rather, the voltage on the 4 ohm tap is half the voltage on the 16 ohm tap. It helps if you think of the equation for power: P = V^2/R. If you have 100W into 16 ohms, the voltage is V = sqrt(100*16) = 40V RMS. If you have 100W into 8 ohms, the voltage is V = sqrt(100*8) = 28.28V RMS. If you have 100W into 4 ohms, the voltage is V = sqrt(100*4) = 20V RMS.
When designing an amplifier from scratch, it doesn't really matter which transformer tap you use. What you are trying to do is obtain a certain amount of negative feedback, which is determined by the ratio of the two feedback resistors (the series feedback resistor from the output and the shunt feedback resistor that goes to ground, which form an attenuator). The tap simply determines the initial amount of voltage applied to the feedback network, which is then adjusted to achieve the desired amount of signal reduction, or negative feedback. "
Since I have the 2.7k NFB resister on the 4 ohm tap and the speaker on the 8 ohm tap how does the above info apply?