Hi,
On the original AB763 circuits, the cathode resistor is shared for V1B and V2B (pins 8 on both V1 and V2 are connected and go through an 820 Ohm resistor). A popular mod on these amps appears to be pulling V1, which supposedly gives the Vibrato channel a stronger signal which will then "push the second gain stage (V4 tube) harder and give you increased sustain, compression and harmomics" (from fenderguru.com). I read on a different forum (
http://www.tdpri.com/forum/amp-central-station/638-drri-v1-tube-pullout.html) that effectively, by eliminating V1, the current going through the 820 Ohm resistor is reduced by 50%, and thus the voltage drop over it is effectively reduced by 50% as well. In looking at an original AB763 schematic, the voltage at the cathode of V2B is 2.1V, so presumably it would then drop to around 1V when V1 is pulled?
I'd be interested in adding a switch to my Hoffman AB763 Super Reverb that would allow me to accomplish the same thing as removing V1 on an original AB763. Since the Hoffman circuit has separate cathode resistors for V1B and V2B, my first guess was that I will simply need to add a switch that will add/remove one resistor from a parallel pair on V2B.
Now, I did some searching and it appears that bnwitt did something similar on his Vibroverb project. From his thread:
http://www.el34world.com/Forum/index.php?topic=3238.0it appears that his mod affects the cathode resistors on both V2A and V2B, and his mods match those found on the Fender Custom Vibroverb (the one with the Diaz mods). Looking at the schematic for the Custom Vibroverb
http://www.prowessamplifiers.com/schematics/images/64%20Vibroverb%20Custom%20Schematic.pdf)
the mod mode shows a cathode voltage of 2.70V (resistor value 2.7K) versus 2.06V for the stock mode (effective resistor value ~1.5K for the 3.3K and 2.7K parallel resistors).
So, now I am a bit confused (nothing new there).
1) On an original AB763 with V1 pulled, is the current really being reduced by 50% and thus the cathode voltage for V2B is also reduced by 50% to around 1V? If so, is the Custom Vibroverb mod that disables the Normal channel something different altogether since that seems to increase the cathode voltage?
2) If I truly just want a switchable mod that replicates the removal of V1, do I want the 3.3K & 2.7K resistor pair on V2B that nearly doubles the value from the stock setting (i.e. 2.7K vs 1.5K), or do I actually want a pair that would reduce the resistance by ~50% (perhaps two 1.5Ks in parallel)?
3) The Diaz Custom Vibroverb mod seems to also have and added capacitor in parallel to the 2.7K resistor (0.68uF) on V2B, and as bnwitt explains in his thread, in mod mode the effective values are thus 2.7K and 0.68uF versus ~1.5K and 22.68uF in stock. What effect/impact does this added capacitor have?
Thanks!