The resistance from cathode to ground goes from 820 ohms to 2.5k when the intensity control is turned up or down.
I'm going to get an LED and see this damn thing oscillating.Back in a bit,the saga continues........
Thanks for your help dude!!!
besides an LED or a scope reading, you can usually see a phase-shift oscillator (like this one) oscillate with a voltmeter set to DC or AC on the plate. it'll fluctuate as it oscillates, even with a DMM it is slow enough of an oscillation to make the voltage reading move. when you step on the footswitch, and turn the oscillator OFF, the DC voltage should stabilize at the plate, and the AC between any of the caps will go to 0.
ah yes, your
Rk ohm readings look good,, 820-2.5K:: when intensity is "off",,
Rk=820, when "on",
Rk=820+(2200||5000)=2348
I'm at a loss as to what to suggest at this point.
Sluckey,
how does this tremolo work?: the 2.2M and the intensity control resistance form a voltage divider and attenuate the oscillating AC single to some level that goes through the 820R and appears on the cathode. (this is were I start to fall off) that oscillating signal changes the bias of the gain triode? because the 50uf holds a bit of the AC voltage above the natural self-biased DC of the triodes and varies the DC of
Rk, and thus the bias of the gain stage?
One thing that confuses me,, the oscillating signal at the grid of the oscillator triode will naturally appear on the cathode of that triode at some smaller voltage, even without the 2.2M. is the voltage of this naturally appearing signal so small that they added the 2.2M to supply a larger version of oscillator signal on the cathode?