Are you quite sure of the pinout; eg, basing diagram of the 6P1P output tube? (I am completely unfamiliar with Russian tubes)
As I poke around, I see the 6P1P cited as "equivalent" to a domestic 6AQ5, a 7-pin tube. You understand that two tubes can be "equivalent" (which would mean; they have the same heater volts, the same mu, the same ability to dissipate heat, the same ability to handle (say) 350 volts on the plate, the same ability to put out (let's say) 5 watts given 3 volts of drive; and etc; etc; without being pin-compatible or socket-compatible. We speak of a 6AQ5 (7-pin) and a 6V6 (octal = 8 pin) and a 6BQ5 (9-pin) being 'almost the same tube'.
But you obviously cannot place a 7 pin tube in an octal socket. Nor can any of the other tubes I mentioned be exchanged because they are mechanically, physically incompatible. ELECTRONICALLY, they are considered "the same tube". They are "the same tube IF AND ONLY IF the user accomodates the different sockets they use by "translating" the plate is ____ on tube A and the plate is ___ on tube B. The cathode is ____ on tube A and ____ on tube B. For each and every tube element.
You show the input signal going to pin 7 on grid #1 aka "control grid". Just like a 6AQ5.
You show the plate being pin 1, or pin 6. You mean; you can connect to either one? Well that can't be right. (there ARE tubes that do this, but not in this case) So maybe this 6P1P is more like a 9-pin 6BQ5. OK! Let's go check that out.
Let's start over.
You show the input signal going to pin 7 on grid #1 aka "control grid". Wait a minute. Pin 7 on a 6BQ5 is da plate!!
That's enough to obliterate any possibility of this working right there.
My opinion is: The pinout you have (and from which you presumably wired up the amp) of the output tube is completely buggered.