A rectifier diode in a valve amp has to pass the peak and rms current levels required by the power supply. A diode has limits on the peak and rms levels it can cope with (whether it's a solid state or valve diode). However those current values don't directly relate to 'a 100W amp'. Perhaps you have a 100W amp with a pair of KT88's, that has an idle B+ requirement of 600V and 100mA, such that each KT88 dissipates 600V x 50mA = 30W.
With a signal, that B+ current will increase - how much will depend on loadline and some other conditions. A quick estimate could be the KT88 plate current reaching 400mA with a 5kPP output transformer, indicating an output power to the speaker of (Ipk)2 x Rpp / 8 = 0.4 x 0.4 x 5k / 8 = 100W, and the average B+ current could increase to about 250mA average, and the power supply could be delivering 600V x 250mA = 150W to the amplifier.
Note that the article refers to '100-200mA' as a comment, for the reason that once a detailed assessment is done, it could well be that 200mA may be an upper limit for a UF4007 when used in a power supply with a lot of filter capacitance and a low DCR winding transformer, especially if the diodes sit in a hot section of the amp and have little cooling, and the amp is in a hot venue.
PS. The diode current is also not the DC output current of the power supply - it is related, but the relationship depends on power supply configuration, so additional information is needed such as measurement, or simulation, or design calculations, or rule-of-thumb, or checking like equipment.