Hi All,
I've installed a 200 ohm (12w) variable cathode resister (rheostat) in my ’68 AC30 to make biasing new output tubes easier.
I'm wanting to check if I’ve done things correctly before powering it up.
I’ve wired a 40R 10W resistor in series with rheostat. Specifically, the (shared) cathode connects to the 40R resistor which in turns connects to the wiper of the rheostat. From there I’ve wired one of the outside lugs of the rheostat to ground, completing the variable cathode resistor circuit. I’ve left the opposite (outer) rheostat lug free (open).
This obviously gives me a minimum of 40R between cathode and ground if the rheostat fails by shorting to ground - if that's ever a thing.
Having said that, I've just read that if/when a wiper from a rheostat comes off its track it's designed to engage the full load of the variable resistor (?).
Either way, my chosen wiring set up avoids the chance of a direct short between cathode and ground.
My choice of wiring is based on my assumption that the most catastrophic possible failure situation is if the shared cathode shorted directly to ground - allowing for excess levels of current to build in the output tubes. Conversely, if the cathode becomes open (completely disconnected) it prevents any and all potential for meaningful levels of current to flow in the tube - and while this latter failure will stop the amp from working it’s less likely to do any catastrophic damage to the output tubes and output transformer etc.
Or am I completely off track in that assumption?
Kind regards
James