The circuit works like this...
Thanks. But the sidechain
Like I said, I'm not an engineer, but I'll try to figure this out. My analysis:
Input pot defines how much sampling 6C4 will do. Then that signal is amplified and sent to diodes. Left side of 6AL5 lets the positive lobes of signal to ground. Right side of 6AL5 lets the negative lobes of signal to C .22uF right after diodes. Cap rectifies the negative signal. Level pot mixes the rectified signal and ground. Now to the actual magic. The job of the suppressor grid is to keep electrons from bouncing off the plate, normally it is tied to ground, right? So, to get the pentode off of "beam tetrode mode", the suppressors voltage shifts when sidechain hits it with DC. This DC would be rippled, negative spikes parallel to original signals positive lobes because of inverting in the 6C4.
Is this correct or even close?
What I really can't see, is the magic happening inside the pentode. It looks like the incoming signal to suppressor is negative compared to ground. Does this block the electrons coming towards plate? Screen dissipation would not rise to melting point because it is not tied to plate but a voltage divider. If so, quieter signals would not affect the amplification factor, while louder signals would tame the pentode?
Many questions, many guesses... thank you all for educating hobbyists like me.