OTOH, most people around here will just say "stick anything in there, it works", which seems to be a general consensus when it comes to chokes as of late.
People do say that regarding a cap-input supply, but only because a choke in those circuits only has to support the current of the preamp tubes and output tube screens.
Also of note, there is an upper limit to the size of the choke you can use, as if you are not pulling
enouhg continuous current, you can not create a big enough B field around the choke for it to do proper regulation, and it all goes to hell.
That's a crucial point. Rule of thumb, the voltage at the first filter cap of a choke-input supply is 0.9 times the RMS voltage you're rectifying. For 500vac, you're talking about getting 450v. If you don't draw enough current, the action of the choke doesn't take place, and the voltage reverts to about 1.4 times the RMS voltage. That would put you at 700v. Not good.... Sounds like a standby to allow the heaters to warm up would be a very imprtant thing to have, not for the tubes (although they could be damaged) but for your filter caps. I'd still feel better about rating that first filter cap for the worst-case voltage.
I went to a reliable source (Morgan Jone's book Valve Amplifiers) and looked up some choke-input supply info. He notes that in the "old days" the solution was to use a swinging choke. You have a very tough time finding those these days, so that's probably out of the question.
He gives a detailed formula for the minimum current draw needed, but then goes on to note an approximation for 50/60Hz power supplies. It's
Currentmin. (in milliamps) = VIn (RMS) / L (in henries).
So for your 500vac transformer (which is RMS volts), you'd divide that 500v by the inductane rating of the choke you intend to use to see what the minimum current draw must be. As an example, for a 20H choke, 500v/20H = 25 milliamps of minimum current draw. The implication is you want a very high inductance rating for your choke.
He also notes that it would seem the choke only needs to be rated for the maximum d.c. load current, but that the choke really needs to be rated in excess of this. Why? The choke generates a magnetic flux in the core proportionate to the size of the current passing through it, and if that flux is too great, it saturates the core and the inductance of the choke falls to zero. Bam! You're back at 700v.
The current that the choke will support is the max d.c. load current and the instantaneous a.c. charging current (meaning the current used to charge the filter caps). So that's
IDC + IAC = Itotal peak current.
He derives a formula for the a.c. peak current. For a 60Hz wall outlet, it's
IAC (positive peak) = VIn (RMS) / [1386 * L)
Vin is the RMS transformer voltage again, and L is choke inductance in Henries.
Here's an example he gave in the book, but with a slightly different formula for 50Hz operation:
"A Class A power amplifier using a pair of push-pull 845 valves requires a raw HT of 1100v at 218mA, and a 10H 350mA choke is available, but is this adequate? The transformer supplying the choke has an output voltage of 1224VRMS, and using the equation for a 50Hz mains:
IAC = VIn / 1155 * L = 1224 / (1155 * 10) = 106mA
Itotal peak current = IDC + IAC = 218mA + 106mA = 324mA
The total peak current is 324mA, so the 350mA is just barely sufficient ... "
That shows that the choke needs to be rated in excess of the peak d.c. load current, which is the current the amp draws from the power supply at max power, not at idle. Once again, a choke with more inductance tends to ease your required ratings.
But in all, you need to flesh out the design a bit more to properly rate the choke. Looking at this info, it's a very bad idea to just "slap something in" when you're thinking about a choke-input power supply.
Jones also notes that regarding the power transformer, it simply needs to be rated for the d.c. load current. He gives an explanation for why, but it's enough to know that's the case.
He does also note that the input choke creates voltage spikes seen by the power transformer. The solution is to have a snubber network, and he notes that the apparently best way of going about this is to fit 2 caps across the choke, with their "center-tap" connected to 0v. What this means is to use two 0.22uF 1kV caps connected in series, then take the outer leads and connect those to the choke to put this pair of caps in parallel to the choke, then connect the junction of the 2 caps to ground.