Obvious:
What happens when the right hand pot is turned full down? (Nothing comes out, wet or dry.)
The apparently complete power supply has no provision for +5V 100mA to power the Belton.
Not obvious:
Where does this go? Inside the amp? In line with guitar?
Subtle:
A reverb spring has loss of 1000:1, so it needs 2 or 3 amplifier stages.
The Belton is unity-gain (0dB); why do you have two high-gain amplifiers?
The Belton input overload is 1.5V. With lefthand pot full-up, and V1 gain near 40, input overload is near 37mV. Guitar outputs can exceed 0.5V, but almost never 1.5V. Why is there gain before the Belton?
Actually the full-up gain won't be 40, because the Belton input impedance is 10K. If the unloaded gain of V1 is 60 with output impedance of 120K, then with the Belton loading it will be more like 3. So the gain may be appropriate... except the loading also loads-down the dry path, which probably should not vary much while the reverb knobs are turned.
The internal mixing inside the Belton
may depend on a low source impedance, (<<10K).
If reverb is defeated (how), then the dry/direct path has anything from large gain to no output at all, depending on reverb pot settings; consistent unity would be expected.
Decode the suggested implementation:
http://www.smallbearelec.com/Projects/ReverbPedalSchematic.pdfFirst opamp is unity gain, shows a high impedance to guitar and low impedance to internal circuits.
Next opamp has gain of 2 for high frequencies and gain of 0.67 for low frequencies, and shows a low output impedance to the Belton.
Through Belton.
The last opamp is a mixer. The topology is odd. The direct path has gain of 0.8 (not unity, but close). The reverb path gain is adjusted in the pot; at full up (down as drawn) it seems to have gain of 0.25. Traditionally I have assumed that BIG REVERB needed gain equal to the dry path; indeed my software reverb can be turned up to reverb 200+% of dry signal. I only use it to sweeten orchestra/choir, no SURF, but even then I may run over 40% reverb gain. Maybe the Belton sound is so "thick" that it does not have to come back as big as the dry signal to be "big"? Alternatively, maybe the Belton's flaws become apparent if returned too large.
I do not know the module; but I think that plan can guide your thinking.
I'm also not sure what tubes bring to the game, if the max signal in/out of the Belton is only 1.5V, 1/40th of what a tube can do, or ~~0.1% THD. The Belton's basic operation eliminates the power tube driver, driver transformer, and coil-slap of a spring-tank; no place to put the little tube quirks which make classic tube reverb delightful. Oh, you could use 12AT7/6F6 and transformer to drive Belton (it's roughly the right voltage!); but then you may as well use a spring.
What JB said: "I think a source follower driving it and maybe fet recovery". Get some cheezy 12VDC supply to feed the JFET drains, regulate 5V for the Belton. If the designer's plan is good, it does not even need gain after the Belton, though it may need a buffer after the dry/wet mixer..... ah, maybe not.