Well, yes... as you found out.
The only formula you can be confident in is that the peak voltage of a sine wave is 1.414*volts RMS. But that doesn't tell you the whole story.
1. The rectifier may drop some amount of voltage, and the drop could vary with the current passing through it.
2. The voltage may be reduced by voltage drop across resistance in the power transformer, as well as any series resistance in the B+. If you have a choke ahead of the OT, it might also result in voltage drop.
3. There will probably be some small voltage drop across the OT primary.
4. The voltage may be less than expected due to smallish filter caps. Small-value filter caps store less charge (not less voltage), which is then more easily drained by a heavy load.
5. If you draw more current from a transformer than it is rated to supply, it won't burn or stop working (unless you go overboard), but the output voltage will sag. You might not be able to predict the sag, because it depends on many factors of the design of the specific transformer.
But here's the real rub: you have measured the voltage the tube "feels," from the plate to cathode. So you have subtracted the voltage across the cathode resistor. That probably accounts for much of your discrepancy.