Assuming conventional full wave rectifier...
You must know the load current and the PT internal resistance/losses. Then you can use tube data charts to get in the ballpark. I've seen lots of people bounce around numbers like this tube will deliver a B+ that's equal to 1.2 times the AC voltage input, or that tube will give 1.3 times the AC voltage input. And while those numbers will give you an indication of how this and that tube will behave in a particular amp, you just can't say that a 5Y3 will yield 1.2 X AC input for any amp. You must know the load current and PT losses.
One thing you can count on though... When you have no load current the B+ from any rectifier tube will be the same as a SS diode, ie, 1.414 X AC input.
For an example, say you have a PT that's rated for 70ma, and you have another PT thats rated for 200ma. Both put out the same no load voltage. Put the little PT in a test jig and increase the load current. The PT will soon reach it's rated current and when you increase the load current beyond that 70ma point, the voltage will begin to drop. The more you increase the load current, the more the voltage will drop. It's called sag. And it's caused by the PT internal resistance. Now, without changing the load current of your jig, replace the 70ma PT with the 200ma PT. The voltage will jump back up because you haven't reached the current rating of the big PT. The big PT has a lower internal resistance and can put out more current before beginning to sag.
It's not quite that cut and dried. The no load voltage from a PT will begin to drop as soon as you put any load on it and the voltage will continue as the load increases. It's not like the PT just puts out a continuous steady voltage until the max current is reached and then starts to sag. This stuff ain't voltage regulated. However, a big PT will sag less that a small PT.