Thanks but my questions are about the meaning of the data about:
indication in Volt
in the impedance row @35W 374.1V
in the primary impedance row 4000ohm 374.1V
in the secondary impedance row 4/8/16ohm 11.83/16.3/23.66V
Start with some assumptions. The transformer you referenced is intended to be a replacement for blackface Pro Reverb, Tremolux, Vibrolux. The assumed output power for these amps is 35w, from a pair of 6L6's.
- From the wheel showing equations, P = V
2/R.
- Assume the 16 ohm speaker load, and 35w output. Rearranging the equation, V
2 = P*R = 35 * 16 = 560. The square-root is 23.66v (RMS).
The same steps are used for other speaker loads.
- Now, calculate the needed primary signal voltage for a given speaker load.
- The primary is 4000 and the secondary is 16 ohms (for our example). Impedance ratio is 4000/16 = 250.
- Voltage is stepped-up/down by the
turns ratio, and the impedance ratio is the square of the turns ratio. So we need the square-root of the impedance ratio to see how voltage is changed. The square-root of 250 is 15.81. This is the turns ratio for 4k:16 ohm.
- Calculate the primary signal voltage: 23.66v * 15.81 = 374.06v
We're a little different from the sheet spec, because we rounded in two calculations.
Now, you use this info to select your output tubes (if you're not simply dropping this in to an existing Pro Reverb, Tremolux, etc).
How much current do the tubes need to allow to pass? 35w/374.1v = ~94mA RMS. This is
not the needed idle current, but how much RMS current the push-pull pair needs to flow to have 35w at the OT primary. Similarly, the push-pull output pair needs to swing 374.1v RMS when looking at one plate to the other.
Let's cheat:
The
Pro Reverb has a plate and screen voltage of 440v, and -51v of bias. Plot this point on a set of curves (the Ec2 = 400v curves on page 7 of the
6L6GC data sheet). Also plot a 1k load line from 440v (0mA) to 0v (440mA).
How far does the plate voltage swing downward until the loadline hits the 0v grid line? 330v. The needed plate swing is 374.1v
RMS, which is ~529v peak. But the total voltage swing felt by the primary is the sum of the voltages of the push-pull plates; one is swinging up while the other is swinging down. Our curves only show 1 half of the primary swing. 529v/2 = 264.5v, so the needed swing is well within the capability of our 6L6 half of the output stage.
What about the current? 94mA RMS = ~133mA peak. Since this is a class AB stage, one side will be cut off during most of the time that the other side is one. So each side should be capable of the full peak current. A glance at the plotted curves shows our 6L6 can easily deliver this.
The info tells us a pair of 6L6's at ~440v B+ is a suitable pairing with this transformer to deliver 35w.