So Sluckey
is right, but I asked my silly questions to show how to figure a starting point from scratch.
Power = Voltage
2/Impedance
4w = Voltage
2/16Ω
Voltage = 8v RMS (for 16Ω tap)
According to
Crown's website, Professional +4dBu line level is 1.23v RMS and -10dBV consumer line level is 0.316v RMS.
We don't know the input impedance of the gear you'll be using, but Crown says 10kΩ is typical. We want a source impedance 1/10th of this, because we want to have good voltage transfer not maximum power transfer (in which case we'd have source impedance equal input impedance).
So we need an output impedance of 1kΩ; let's use a 1kΩ audio pot. That will be your R2.
Figure R1 based on the most-loss situation of dropping 8v RMS to 0.316v RMS for consumer-level gear. Use the formula for a voltage divider, times our known source voltage (8v RMS) and equate it to our needed line level voltage (0.316v RMS). We know R2 will be 1kΩ, so substituting that, we get:
8v * [R2/(R1+R2)] = 0.316v
(8v*R2)/(R1+R2) = 0.316v
(8v*R2)/0.316v = R1+R2
(8v * 1kΩ)/0.316v = R1 + 1kΩ
(8v * 1kΩ)/0.316v - 1kΩ = R1
R1 = 24.3kΩ
24kΩ is a standard value in the E24 5% tolerance series, and is close enough. See the
Standard EIA Resistance Values table.
For +4dBu pro line level, we need to raise the output signal to 1.23v RMS. Using the same process as above and substituting our new output voltage, we find R1 = 5.5kΩ.
We could get very close to that value in the E96 series, using a 5.49kΩ 1% resistor. But let's figure out what resistor to add in parallel with the existing 24kΩ resistor.
Performing some algebra on a common formula for 2 resistances in parallel, if R2 and Rtotal are known, we can find R1 using:
R1 = (R2*Rtotal)/(R2-Rtotal)
R1 = (24k * 5.5k)/(24k - 5.5k)
R1 = 7.135kΩ
7.15kΩ is a standard value in the 1% tolerance, but you can get reasonably close to accurate in a 6.8kΩ resistor in 10% or 5% tolerance ranges.
Unfortunately, I can't draw this right now (chasing a toddler), but use a 1kΩ audio pot, with a 24kΩ resistor in series (your -10dBV setting) and a SPST switch which can add a 6.8kΩ resistor in parallel with the 24kΩ resistor (your +4dBu setting). Power dissipation even with the speaker unplugged will only be a couple milliwatts, so 1/2w parts are fine.
There's a little slop, but that may help you get a strong enough signal when you're playing very cleanly and well below the full 4w output; if the signal is too big or the output really tends towards 5w you're able to trim the signal down with the pot.