... for the electrolytic capacitor 250v (or 300v better) 220uF
Is this a typo(220uF) or does a doubler need bigger caps than normal (20~40uF)?
Not a typo.
Full-wave rectifiers (regular or bridge) pass current during both halves of the incoming a.c. cycle, and have 120Hz hum (in the U.S.).
Half-wave and voltage doublers effectively pass current during only half of the incoming a.c. cycle, and have 60Hz hum. The lower hum frequency requires more filtering than 120Hz, becuase the power supply components are essentially less effective filters.
The generalization about the doubler above is technically wrong: During one half of the incoming cycle, one of the 2 caps is being charged, while the other gets charged during the other half-cycle. But since you could say that the total charge of the filter cap totem pole happens only once during a cycle, you could probably argue the filter is effectively only charged half as often as in a full-wave rectifier. Hum frequency is 60Hz regardless.
So the filter caps also need to be bigger than "normal" because current is being sucked out faster than it is pouring in if the rectifier were full-wave. In other words, 2 reasons to use bigger value caps. This is the reason doublers are usually only used in low-current supplies: the current is sucked away from the caps such that if the current draw is too high, the voltage drops
considerably.
I have a preamp I was thinking of using a doubler with because of the low voltages. It originally used a half wave rect ...
Do you want an output voltage twice what you had with the half-wave rectifier, with poorer voltage regulation (maybe as much as 100v sag in some cases) and needing bigger caps for same/higher hum? If so use the doubler.
They good circuits, but not usually a great choice for most applications. If you're just power a few 12A_7's, then you're probably alright.
It originally used a half wave rect, but it has has no seperate 6.3 heater winding. Instead it used a 6.3 tap, so the ground was common(in the above schematic picture a tap between A and B. So B to A is 140V, B to tap is 6.3V). would it be OK to use that tap with the doubler? This would elevate the 6.3Vs "ground" to half the B+.
I'm having a hard time visualizing what you're describing, because I'm thinking a couple statements are incompatible with each other.
If this is a preamp, and only powering a few 12A_7's, it sound like the designer did something tricky. It's best not to mess with something tricky without
all the information that went into designing it. So what is this preamp?
You also can't have a tap that's part of the secondary that only outputs 6.3vac, while at the same time having one side of the 6.3v at half-B+. Wihtout any other info, I'd say don't do what you were considering. Either use the PT as in the original preamp, or post more info on the preamp or its schematic so we can figure what's happening.
I was gonna build a prototype VD but all i could find is 220-160v e-caps, will these work for now? ...
No.
... I have a couple amps on bench with VD they use 100-150v caps in the doubler as do most ive looked up on net is there a reason for the higher value?
You have to be guided by the transformer
you're using, cause the others on the 'net may be different and with different ratings.
You measured 140vac on the transformer winding. 140v * 1.414 = 198v peak. You need a cap that's rated for at least 200vdc, and higher would probably be a good idea (for days when your wall voltage rises).
You'll be stacking 2 of these in series, for a total rating of 400vdc, which you need to ensure caps don't fail at turn-on. Even with that rating, your B+ in use will probably drop to 300-350vdc (I'm banking on the lower end of that).
Here's how the doubler works:
When point A is negative compared to point B, D2 is forward-biased and charges C2 to 140vac * 1.414 = 198vdc. On the next half-cycle, the polarity of the seocndary changes, and point A is positive compared to pont B. Now D1 is forward-biased and charges C1 to 140vac * 1.414 = 198vdc.
But C1 is stacked on top of C2, so the B+ is 198v + 198v = 396vdc.
Until you draw current, in which case the voltage sags.