the tube rectifier is a 6x4 tube and the DC voltage measured after the rectifier is 270v
assuming that a SS rectify will give a DC of ~315v I can estimate the voltage drop in 45v
Is possible to estimate which is the current consumption of the circuit that gives as result a drop of 45v using a 6x4 tube ?
The current that causes the voltage drop is the entire B+ current being drawn, because the rectifier must pass all current drawn by the B+ supply.
This question is specific to a circuit but I would like to know how to solve it as to apply also to other circuits with other rectifier tubes
So you really want to know how to estimate the output voltage of a tube rectifier in other amps, right?
How exact do you need to be? If just "close enough" then Tubenit has posted a chart with observed multipliers when going from a.c. input voltage to d.c. output voltage for a number of common rectifiers in a cap-input power supply.
If you want to be exact, download a copy of Radiotron Designer's Handbook, 4th Edition from the
Library of Information (download link is just after the "Windows Printing Tip" box). Go to Chapter 30, Section 2 pages 1170-1179.
An example takes up most of page 1179, and has 14 steps and 8-9 graphs to use in lieu of complex calculations.
The problem is
many factors impact the actual output voltage, including information about the power transformer winding resistances, winding ratio, input a.c. voltage, peak and average diode resistances, any additional series resistance, load current, load impedance, filter cap value, etc.
You also have to know a lot about how your proposed amp circuit will operate. If class A, you can simplify and assume load current stays essentially constant, but for class AB amps you may have large changes in amp current during operation. If you want to predict how far the voltage will sag under full power conditions, you'd have to take those changes into account and calculate the performance separately for idle and full-power.