Most of the tech stuff i've been reading shows the cap discharging through a load resistor ...
Equivalent circuit.
It's easier to draw a resistor than a mass of circuitry. If there is a voltage across a resistor, then there is a current through it, which depends on the amount of resistance (ohm's law). So any load could be represented by a resistor which draws the same current from the power supply.
It's obviously getting charged from the PT and building up a voltage but then my thinking is how is it discharging? through what route?
What is the main cap connected to?
+ end of Main Filter cap -> OT center tap -> output tube plates -> through tube -> Ground -> - end of Main Filter cap
There is also the parallel path of the choke and screens, as well as the portion of the supply which feeds the preamp. But output tube plates draw the majority of the current.
So let's say you have a 4kΩ plate-to-plate OT. The power supply cap is connected to the center-tap, so you might say you have 2 parallel paths through output tubes to ground. You could say each half of the OT primary is 2k, and those halves are in parallel. While you'd think that's like the supply seeing a 1kΩ load resistor, in fact when one tube is conducting more the other is conducting less, so until one of the tubes is completely cut off it looks to the cap like a 2kΩ load.
So for calculation with a 2-output tube Marshall, you might assume you could replace the output section with a 2kΩ resistor (or 1.7kΩ if your OT is 3.4kΩ plate-to-plate).