The two 470k in series makes 940k (1M) that is AC-tapped off the plate of the stage and fed back to the un-bypassed cathode of the same stage (where the signal is out of phase with the plate).
Ok, I missed that before when DL said "local FB" it just struck me now. The local FB is from plate to cathode on V2a.
But the 2x470K junction is still tied to the grid of V2b. They saved a coupling cap doing it that way but did they wire it up that way for another reason too?
I was thinking (AC) NFB injected into the grid (along with the AC plate signal of V2a) of V2b because V2a's cathode is un-bypassed.
They should cancel each other out somewhat. The more the plate signal developed then more cathode signal developed and that's gonna act like a compression circuit.
Well depending on how much the plate signal swamps the cathode signal. The more the plate swamps the cathode the less the compression effect down to not happing at all.
As it happens, just the fact that the cathode is un-bypassed will be adding cathode current feedback into the stage.
Which stage, V2a or V2b?
The plate-to-cathode local NFB dampens the effect of the cathode current feedback somewhat.
So the plate-to-cathode local NFB dampens the effect of the cathode current feedback somewhat,
to V2b?
Why "current" FB and not voltage FB? Since the cathode of V2a is un-bypassed there's AC signal voltage. Or is it both at low a Z?
And isn't the bias point of V2b changed a little by standing V2b's grid leak on top of V1a's K R? That K R has got to develop a few acv.
Brad
