... 6FQ7. Pin 1 (plate) is 70vdc pin 3 (cathode) is 2.83vdc ...
Do you get similar voltages on pin 6 & pin 8 of V2?
You didn't give voltages for the power supply, so there's no context for plate and cathode voltages of the tubes. But V2 pin 6/8 has power supply node and plate/cathode resistors and could be a guide (in spite of being a 12AX7 instead of a 6CG7).
... Possibly the transformer, maybe that .003 is NG and shorting out the tranny. ...
I think the reverb transformer primary is open (or near-open).
... pin 6(plate) is 3.2vdc and pin 8(cathode) is 11mV. ...
The plate is at 3.2vdc; if the tube's plate load is shorted, you would expect the full supply voltage at the plate. But this supply node can't be at 3.2vdc, because you're saying other tubes have normal voltages which includes V2 (fed by the same supply node as the 6CG7). So we can conclude the plate load (the reverb transformer & parallel cap) aren't shorted.
When there is plate voltage but it is very low, you would expect that the tube is drawing very heavy current causing a very large voltage drop across the plate load. But the plate load is a coil of wire, and might only be 100-200Ω (maybe less, maybe a bit more). If the supply voltage is 150-200v, that would mean 147v or more is dropped across the reverb transformer primary which implies 147v/200Ω = 735mA or more. The reverb transformer primary would have burned open by the time that much current flowed.
If the plate voltage was dragged low by excessive current as described above, the cathode resistor should have a large voltage across it because of the large current flowing through it (Ohm's Law). The cathode resistor is 680Ω, so if 735mA was flowing through it as calculated above there would be 680Ω * 0.735A = 499.8v across it. Again, this is impossible due to the assumed supply voltage; it also implies 499.8v * 0.735v = 367w+ dissipated by the cathode resistor. It would have long since burned open.
If the reverb transformer primary were completely open, there would be 0v on the plate and cathode (infinity ohms gives infinity voltage drop, 0v left on the other side connected to the plate). It's possible that 11mV measured with some meters is just error and really represents 0v, but the 3.2vdc on the plate is more than just error.
If the 11mV is an accurate reading, then there is 11mV/680Ω = 0.016mA passing through the cathode resistor and also through the "plate load". You didn't give supply voltages, but if this node is indeed 150vdc that leaves ~147v across the reverb transformer primary while flowing 0.016mA so its resistance is 147v/0.000016A = ~9MΩ. Close enough to open to not work but not infinity so some voltage leaks through.
Turn the reverb unit off, make sure filter caps are drained and measure the resistance of the primary. I can't imagine a good one being over 1kΩ, maybe much less. It will be obvious if it's closer to 1kΩ or 9MΩ. If the resistance seems good & low, the remaining possibility is a partial short-circuit from the plate-end on the reverb transformer to ground external to the tube socket and the transformer. The other failure that could fall in this category is a short from the primary to secondary, which is grounded.
... what is the purpose of the .003 cap from node A to pin 6 of the 6FQ7? ...
It reduces high frequency response. Maybe to tame a tendency to oscillate, maybe to shape the tone of the reverb signal.