I was looking into the 6N2 on audiophile pages ... They didn't talk numbers, just what "seemed" better for a given amp.
Audiophile sites ( with few exceptions) are worse than a waste of time if you need to know anything technical; you won't duplicate someone else's results without everything in your setup being identical to theirs (even then you may disagree with their subjective evaluation).
Reading in the web often 6N2P-EV tubes are defined as to have a gain slightly higher than the 12AX7 tube, 110 instead of 100 but in Wikipedia http://en.wikipedia.org/wiki/6N2P the gain of a 6N2P tube is defined as lower than the 12AX7 ...
... my question is if the 6N2P-EV tube may be considered to have the same gain factor, a higher gain factor or a lower gain factor compared to the 100 gain factor of a 12AX7 tube ...
Amplification factor is not the only thing that dictates gain in-circuit; this should be apparent because a 12AX7 (with an amplification factor of 100) will exhibit a gain of <1 in a cathode follower. So how the tube is used matters.
Additionally, Amplification factor is only 1 of the 3 triode characteristics (the others being transconductance and internal plate resistance). Amplification factor is the characteristic most used for
an initial evaluation of voltage amplifier triodes because it is the least-changing characteristic of the 3. See the 1st graph below, and notice that Mu is the most constant as the tube's plate current changes. As plate current rises, transconductance (G
m increases and internal plate resistance r
p decreases. As a result, you will only truly know what behavior a triode will exhibit if you evaluate the triode's characteristics at the operating point of the actual circuit.
Back to gain in-circuit... For a plate-loaded triode, amplification at the plate output is given by:
A = μ * [(R
L / (R
L+r
p)], where
A = Voltage Amplification ("gain at output")
μ = Triode Amplification factor
at the operating pointR
L = Plate Load Resistor
r
p = Internal Plate Resistance
at the operating pointIf you know how to calculate the voltage output of voltage divider, you will notice "μ" in the equation above looks just like raw voltage input to a voltage divider, while the rest of the equation is showing that the internal and external resistances divide this value up. In plain language,
with a given plate load resistor, if the internal plate resistance is made smaller, the result is a greater percentage of the tube's possible gain. If
everything else stays the same, making the plate resistor bigger gives more gain.
One way this is done in practice is to increase the plate load resistor of a tube to get more gain. The problem is that with a fixed supply voltage, making the plate load bigger reduces the total voltage across the tube, which decreases tube current and makes internal plate resistance rise (look again at the triode characteristics graph to see this in a 12AX7). So gain may go up, but not as much as you might expect because the rise in internal plate resistance offsets the gain increase.
Another trick is sometimes called a "Mu Follower" where an active plate load is used instead of a plate load resistor. This is usually a transistor or FET constant-current source, whose current does not change with varying voltage. This looks to the tube like a nearly-infinite resistance (Ohm's Law, R = Voltage/Current; if Voltage gets big but Current stays constant, then R appears big), and when you apply that to the equation above then gain at the plate is nearly equal to the tube's μ.
So how about actual voltage amplification for the 12AX7 and 6N2P?
Assume the published μ of 100 for each tube is the same (any individual tube might vary above or below this).
Assume each tube exactly follows its published curves (any individual tube might vary above or below this). We would pick an operating point (plate voltage, bias voltage) and plot a tangent to the grid voltage curve at the operating point. I did this for the 12AX7 and 6N2P below. The result was that the 6N2P's r
p was lower at 48.4kΩ vs. the 12AX7's 50kΩ.