p.s.: do you think an electrolytic rated for 100v will be enough as to smooth the elevated DC ?
The elevated voltage is already smoothed by the power supply. And after it is divided-down, any ripple present is reduced by the voltage divider, along with the desired d.c. reference. The 47uF 100v cap is working against 195kΩ to reduce ripple to the reference further. For 120Hz ripple, the 47uF cap looks like ~28Ω; 5v of ripple at the 1st power supply filter cap will be reduced by the 195kΩ resistance and the 47uF cap to 627mV (~8:1 reduction) with less starting ripple being even smaller.
Further, because this is applied to the heater center-tap, both ends bounce up and down with any ripple left.
"But wouldn't the cap possibly see the B+ voltage at turn-on? Shouldn't it be rated for more than 100v?"For the Tweed Bluesmeister, the steady state is B+ of 414v and a reference voltage of 41-42v. The divider passes ~1.9-2mA of current, and drops ~372v across the 195kΩ resistance. The worst-case happens at switch-on, when the B+ rises to 325v*1.414 = 460v (due to no current draw) and the 47uF reference divider cap looks like a short-circuit due to no charge/no voltage. With a full 460v across the 195kΩ resistor, it will pass ~2.36mA and the 47uF voltage will rise from zero up to the desired 41-42v. So the 100v rating of the cap is ample, and the resistance will dissipate about 1w (hence the 2w total rating of a pair of 390kΩ 1w resistors in parallel).