I'm curious about something.
Fuse sizing is a bit of a mystery to me, but thinking it over, I may have come across how it all works in general.
The reason I'm asking, is the Vox AC100/2 I've built seems to chew threw 3A fuses, and I ended up putting in a 6A on accident for a while and although I blew it too, it was something I knew about, i had a high power part of the circuit accidentally right next to ground and it arced and burnt the 6A. Otherwise the 6A really ran a long time. ( just didn't realize I'd put that in).
The original Vox AC100cph has a 6A fuse not a 3A. The '65 Vox AC100/2 circuit calls for a 3A.
I started trying to make sense of 'why' when something dawned on me. Isn't this just a simple 'ohms' law issue? In the old Vox amp, the voltages were suposed to be 30 volts lower. Am I just now, at a higher voltage with the same circuit, guaranteed to draw more amperage? If I were to think in those terms, Lets just say we have 3A, and 470 volts it should have at A. (IT actually has about 500 in this amp) If that's suppose to be less than 3 Amps, then with that math: R = I/V so I'd have 470/3 = or 156.667 ohms is the theoretical 'resistance' that would draw this current. Then if I were to push that up to 500 at the same 'resistance' : 500/156.667 that would be 3.19 A. If the circuit is already near that level, and now we're baselined over it, doesn't that mean I need to raise the fuse? Would a 6A be too much though? What should I use? 4, 5?
Or am I doing the math all wrong, and this isn't how you do fuse calculations?
~Phil