PRR posted while I typed.
So, this might also work to swap in 6L6s into Doug's 6V6 Plexi?
Your PT has a huge amount of 6.3vac current capacity. So yes, no problems just popping the 6L6's in.
Why do I keep harping on the 6.3v? A 6V6 draws 0.45A of heater current (0.9A total for 2x tubes); the 6L6 draws 0.9A of heater current (1.8A for 2x tubes). You'll want to verify your PT's 6.3v winding has an extra ampere of current capacity when swapping.
I know the Plexi is not Cathode biased, so as long as I biased the 6L6s for output the OT can handle it might be OK?
What I mean is to calculate a bias voltage that gives the 6L6s 18W or less output.
My PT has more than enough heater and HV current available. 
You can't "bias the 6L6 to get 18w of
output power"... You can only bias to set the idle dissipation (heat in the tube plate).
You can apply more negative volts if the tube is redplating during actual signal conditions, which amounts to cooler idle bias.
- Output power will be a function of output transformer primary impedance, supply voltage and power transformer current capacity. Say you have 285v of supply voltage, and the 6V6 can pull its plate as low as 50v on signal peaks (corresponding to the area of the knee at the 0v gridline on the plate curves). Then peak plate voltage swing can only be 285v-50v = 235v.
- If your OT is 8kΩ of primary impedance, then if the tubes stay class A (never run to plate current cut off), the load to one side is 4kΩ; if class AB, the load at the peak will be 2kΩ.
- Given the 4kΩ load to one side in class A, 235v peak equates to a peak current draw of 235v/4kΩ = ~59mA.
- Peak power output will be 235v peak * 0.059A peak = ~14w peak; or 14w peak/2 = 7w RMS
- If the output stage actually runs to class AB (would have to verify with plate curves at the correct G2 voltage), then 235v/2kΩ = ~118mA, 235v * 0.118A = 27.7w peak = ~14w RMS
If you plug 6L6's in the same circuit, and even if the PT can supply well over 300mA, you will still only get 14w RMS of output when using the same 8kΩ plate-to-plate OT. That's because when the bigger tubes attempt to draw more a.c., the current is pulled through the OT primary impedance to that tube, so there is an a.c. voltage swing happening to swing plate voltage towards ground, and the tube runs into its saturation voltage (the voltage where the knee of the 0v gridline occurs). Below that plate voltage, current drops rapidly.
... if I biased the 6L6s for full output I could possibly smoke the OT with that much power.
The power rating of the OT is
indirectly associated with current-handling capability. It directly relates to the size of the core, and how much power can be passed from primary to secondary, at some specified bass frequency. You can pass more power through most OT's than they're rated to handle, but bass response will be shaved off (and possibly treble response). OT's on vintage Fender amps, especially the smaller tweed amps, are tiny compared to hi-fi OT's rated to handle the claimed power of those Fender amps.
Really tiny OT's (or those with
very high primary impedances) typically have thinner-gauge primary windings. That's where you have a risk of burning the OT. You generally won't burn a 8kΩ OT by plugging in 6L6's, because the current drawn won't really go up much (as explained above), and because the wire itself is thick enough to handle the current even if it did go up.
Usually, the OT gets burned because of some other fault in the amp, or due to a build error which pulls excessive current through the primary.