... -5vdc momentary at clipping ...
EDIT: here's a link to the whole schematic;
http://el34world.com/Forum/index.php?topic=20705.0 ...
I went surfin and found this on pre-amp blocking distortion;
http://hiwatt.org/2_mod.html
the -14v reference seems to be what I'm experiencing ...
I've been meaning to reply for a couple days... Yes, you're almost certainly experiencing blocking distortion. The tip-off is a grid which should be at 0v now has a negative voltage on it (and pretty big compared to the tube bias).
You're slamming V2-b with a too-big signal. You have an output section which only needs ~15v peak, and also have 4x 12AU7 gain stages which should be able to manage a gain of ~12 per stage.
You've got a number of gain-loss elements.
- There's a Master Volume; I'll assume it's at max throughout the below.
- The split-plate-load in V2-b means you probably have a gain of 6 at that stage.
- I'll arbitrarily guess the James tone stack is -20dB, or a "gain" (loss) of 0.1.
- I'm not gonna analyze the impact of the 47kΩ and 0.01µFat the plate of V1-b, except to say it drags down the output of that stage (adding to the loss due to the tone stack) and probably causes V1-b to distort earlier. (requires loadline investigation, and I'm tired...)
- The Guitar channel volume is a loss of ~0.25 at a rotation between 7 & 8 (out of 10).
- The 470kΩ on the Guitar channel's wiper has a confused interaction with the Aux channel volume and its 470kΩ & 220kΩ resistors. If the Aux channel volume is at max, the other resistors impose an additional loss after the Guitar volume of ~0.38. But if the Aux volume is at 0, the loss is ~0.24. The extra resistors don't provide the isolation you appeared to have wanted...
So working output to input, you need:
- 15v peak / 6 = 2.5v peak at the grid of V2-b for full output (MV at max)
- 2.5v peak / 12 = 208mV peak at the grid of V2-a for full output
- 208mV peak / 0.1 = 2.08v peak at the output of V1-b (+/- depending on real effect of the tone stack loss & 47kΩ to ground)
- 2.08v peak / 12 = 173mV peak at the grid of V1-b for full output
- 173mV peak / 0.24 = 722mV peak at wiper of Guitar channel Volume for full output, with Aux at 0.
- 722mV peak / 0.25 = 2.89v peak at plate of V1-a for full output with Guitar channel Volume at ~7.5.
- 2.89v peak / 12 = 241mV peak at grid of V1-a/Guitar input jack.
Confused yet? Me too... It sure looks like you've got a whole 12AU7 you don't need to use because of haphazard boosting/cutting/loading, because the input jack is only as sensitive as V2-a's grid.
If you haven't gone through the above, you also don't know if you're slamming the input jack with a much bigger test signal than the output stage can handle. I don't recall seeing you mention your test signal level...
So what to do? You may want to ditch the funky arrangement of the Aux channel, unless you're certain you need (a variable) loss there to the Guitar channel. Having both the split-plate-load of V2-b and the Master Volume seems silly (2 loss methods at the same spot in the circuit?), when there is no voltage divider (or other loss mechanism) between V2-a and V2-b. I'll leave it to your taste whether the 47kΩ and cap leading into the tone stack is useful.
Normally, a guitar amp would distribute voltage dividers between each stage (kinda like fixed volume controls) to keep late stages from being driven hard enough to begin grid blocking. See
this Marshall amp; there are voltage dividers (loss networks) between the 1st three gain stages, which also shape frequency response. They prevent grid blocking in the 2nd & 3rd gain stage, and also cut bass to keep the distorted sound punchy.
Mark Huss' solution was to slap large series resistance to slow the charging of the coupling caps when slammed with big signals. You could do that or use the voltage divider method above to ensure signals never get big enough to cause grid blocking.
Regardless of the method you choose, make sure you're not creating flase gremlins by using an unrealistically-big signal at the input jacks.