... trying to confirm why fender used a 29k primary impedance for the reverb driver transformer. ...
Do you know how to
draw a loadline for a single-ended power stage? Have you learned how to graphically determine a tube's plate resistance from its data sheet & an operating point?
You may have to download & zoom-in on the image at the bottom. It is a set of 12AT7 curves from the 3rd page of a
12AT7 data sheet.
I snagged a
silverface Deluxe Reverb schematic, and noted 6v across a 680Ω cathode resistor and ~400v supply on the other side of the Reverb Transformer.
The data sheet shows a single-triode, so we get half-current on the data sheet curves.
Since we have two triodes in parallel, this implies two 58kΩ loads in parallel for a total load impedance of 29kΩ. The curves will show a single load resistance (58kΩ), and twice the internal plate resistance compared to parallel triodes.
6v / 680Ω = 8.8mA ---> a single triode passes 4.4mA, let's call it "4.5mA" to make graphing easier.
The schematic says, "410v" but 400v is easier for graphing, so I drop a big Green dot at the operating point: 400v and 4.5mA.
You note the Reverb Transformer impedance is 29kΩ; our load for a single triode is then 29kΩ x 2 = 58kΩ.
We need a loadline through the operating point. 400v / 58kΩ = ~6.9mA, let's call it 7mA to make graphing easier. The Red loadline starts at 0v and (7mA + 4.5mA =) 11.5mA. The line passes through the operating point at 400v and 4.5mA. This defines a ~58kΩ loadline because (400v - 0v) / (11.5mA - 4.5mA) = 400v / 7mA = 57kΩ plus some rounding error.
Now we calculate power output:
A Class A amp has a limit of clean output while swinging up to 2x idle current and down to zero idle current. So I used a Blue line along the loadline to a current of 2 x 4.5mA = 9mA. The plate swings down to 140v. As a check, 58kΩ x 4.5mA = 261v, and 400v - 261v = 139v (close enough to "140v").
Multiplying the change from the operating point to this peak found with the Blue line gives us Peak Power:
(400v - 140v) x 4.5mA = 1.17 watts
RMS Output Power is 1/2 Peak Power, or 585 milliwatts. But then we have two 12AT7 triodes each contributing the same power for 1.17 watts.
We figure the internal plate resistance of the triode:
The internal plate resistance is defined by a line tangent to the grid-bias curve at the operating point.
I estimated a compromise slope between the -6v and -7v curves, and plot it as a Purple line.
The line has endpoints of voltage at 500v and 290v. There are endpoints of current at 8.5mA and 0mA.
Internal Plate Resistance (rp) = (500v - 290v) / 8.5mA = ~24.7kΩ
Note: 24.7kΩ x 2 = ~50kΩ ----> the load is nearly 2x rp, where theory predicts maximum output power.
Also, this is the rp of a single triode; 2 triodes in parallel then have an rp of 24.7kΩ / 2 = ~12.4kΩ which is mighty-close to 1/2 the Reverb Transformer load impedance of 29kΩ.