I couldn't help but notice that the 3.3M/10pF network and 1M driver grid leak looks a lot like a feedback network for the reverb circuit.
Make sure you see the "channel mixing" and "voltage divider" first that exists between the Dry and Reverb paths of, say, a
Deluxe Reverb.

Pretend for a moment that the Reverb control is all the way down. That means the left-side of the 470kΩ is grounded, and the 470kΩ is in-parallel with the 220kΩ. The Dry signal has a voltage-divider of 150kΩ / (3.3MΩ + 150kΩ) = 1 / 23 ---> 0.0435x
Pretend the Reverb control is turned up: it is on the left-side of the 470kΩ resistor, and sees a voltage-divider composed of 470kΩ and 220kΩ. The 3.3MΩ is there (and there are paths to ground on its left-side), but it's >10x bigger than 220kΩ, so its impact as a parallel path is small. The Reverb signal has a voltage-divider of 220kΩ / (470kΩ + 220kΩ) = ~1 / 3 ---> 0.319x
Can Reverb sneak-back through the 3.3MΩ?
The left-side of the 3.3MΩ has a 1MΩ to ground, in parallel with a 100kΩ plate load to "AC Ground" at a filter cap. That's a total resistance of 90.9kΩ (even less if you choose to include the parallel resistance "looking into the plate" of the tube-stage there). So this sneak-back path also has a voltage-divider present of ~91kΩ / (3.3MΩ + 91kΩ) = ~ 1/37 ---> 0.0268x.
One could argue the 10pF bypasses this divider some, but only above ~5kHz.
I'd worry about mechanical howl from the tank before worrying about feedback through the circuit (though your point about a failing shared bypass cap is well taken).