there is letterally a mountain of stuff in front of it
Franco
Do you own climbing gear?

I'm going to attempt Merlin's "Designing a Pentode Gain Stage the Easy Way" process.
So, if I want a gain of say, 80: The 5693 datasheet gives a gm range from minimum to maximum with 1650 uMHO as the average. That's 1.65mA/V, so 80 divided by 1.65mA/V = 48,484 ohms, or a 47K plate resistor.
With a 300V plate supply, the load line hits 6.4mA. I'll just pretend the -1V grid curve is my 0V curve (Merlin says to draw one in where we want it), and levels off around 7mA (the load line passes a bit low through the knee).
Looking at the 5693 Average Characteristics graph, 0V and 7mA lands a bit less than halfway between the 100V and 75V screen curves, so I'll fudge it at 85V screen voltage. According to the graph the tube reaches cutoff at Vgk = -4.8V. Biasing warm would be about -2V with a plate current of about 3.2mA.
5693 Anode current is 3mA and the screen is .85mA, so the ratio is 3.5. So, 3.2 / 3.5 = .91mA screen current.
300V - 85V = 215V. 215 / .91 = 236,200; a 220K resistor is closest.
Cathode current is 3.2mA + .91mA = 4.11mA. 2V / 4.11mA = 486.6 Ohms, so a 470 Ohm cathode resistor is close.
Finally, I have:
Plate resistor - 47K
Screen resistor - 220K
Cathode resistor - 470
Hopefully, my math is correct and these values would give a gain of about ~80.

I did make an error in my calculations, and did my best to fix it.