Not to hijack, but HPB... if I understand you correctly, you can lower B+ by using a lower value cap coming off the rectifier tube?
The voltage at the PT secondary is a.c. If you have a grounded CT, then then voltage is referenced to ground and both rises about 0v to a positive maximum, and goes below 0v to a negative maximum. The rectifier lops off the negative portion, and only conducts during the positive portion.
So the natural output of the rectifier is constantly moving from 0v to some maximum. If you know the RMS voltage, you can calculate the peak voltage of a sine wave (or half-sine in this case). The peak is 1.414 times the RMS voltage; if the PT voltage is 320vac (or 320v RMS), and the rectifier has zero loss, the output is moving from 0v to 320 * 1.414 = 452v
If you connect a cap to the output of the rectifier, and you draw zero current, the cap will charge to 452vdc and stay there. As soon as you draw current, the voltage
might drop, and usually does. If the current drawn is due to a short-circuit, obviously the voltage must drop to 0v.
The ability of a capacitor to maintain the voltage level following the rectifier is a function of its capacitance. The bigger the cap, the more energy it can store and release over time. If the cap is small, it will result in a lower output voltage than a bigger cap. How much lower is question answered with a series of steps that few of us bother to take, and that would have to be shown at a later time. Or read the rectifier section of the Radiotron Designer's Handbook, Vol 4, or a couple other old engineering books.
I don't suggest it as a catch-all way to drop supply voltage. But a number of suggestions to obtain a low supply voltage in a new build were given and set aside in a search by Bigdaddy to make a low-volume amp. We had already suggested choosing a smallish PT, using the VVR circuit (or powerscaling or similar) to drop voltage, applying a bucking voltage to a PT primary or secondary, etc. This was a last-ditch suggestion to fine-tune a supply that is otherwise close to the desired voltage but too high.