Wow, that threw me for a loop. Are you saying it's a 97V battery? (-) terminal at -7V, (+) terminal at 90V and 0V is a virtual point within the battery? Whew!
So is this a fixed bias or a cathode biased amp?
This is a back-biased amp. Or you could call it fixed bias, but developed in a back-bias manner.
The battery is 90v. The output tube cathodes (which are directly heated, so they are the filaments too) have one side connected to ground. So do all the other tubes. A resistor is placed between ground and the battery - terminal. That means all current for the amp is drawn through that 350Ω resistor, and creates a 7v drop across the resistor.
However, the location of the circuit ground and the direction of current through the 350Ω resistor make it appear as 7v "below ground" or -7v on your meter when the black lead is touching ground. So the 90v battery - terminal also looks like it's at -7v, and so the + terminal will measure 83v when your meter's black lead is on a ground point.
After all, "ground" is only a reference point you choose to call "0v."
The -7v developed across the 350Ω resistor is applied to the output tube grids to bias them. But there's not a true fixed bias supply, just the back-bias resistor. Looks like the entire amp's B+ supply only draws 20mA from the B battery.