use a pot to replace Rk temporarily
my thought is not to change Rk(total), just split Rk = R1+R2(bypassed). ...
Imagine a 1kΩ linear pot in series with a 500Ω (or so) resistor. Perhaps the resistor to tube cathode & "top" of the pot, bottom of the pot to ground, wiper connects to your bypass cap +, and bypass cap - to ground.
If you know exactly how much gain you need, this may be pointless. Then again, it's a fairly long equation to calculate the gain due to a partially-bypassed cathode resistor. The pot/resistor/cap is much faster, assuming you have the parts on hand.
Otherwise, look at your proposed circuit: The resistance to use for a -3dB calculation is the resistance of R2 in parallel with [R1+(Rp+ra)/(Mu+1)].
R1 = unbypassed portion of the cathode resistance
Rp = Plate load resistor
ra = internal plate resistance, at the operating point
Mu = Tube amplification factor
The end result of the equation will be a resistance somewhat smaller than R2 itself. Which also means it's smaller than the original total value of Rk, and with the same bypass cap the -3dB point will be higher by some amount.
How much? Don't know unless you calculate it. How much matters? I don't really know, but I'll know it if I hear it. Which is the real reason I suggested finding the answer to your question empirically...